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anonymous
 5 years ago
What is the solution for w:
w^418w^22=0
anonymous
 5 years ago
What is the solution for w: w^418w^22=0

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anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0http://www.algebra.com/algebra/homework/quadratic/Quadratic_Equations.faq.question.332342.html

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0yeah, it looks like that one would be best done with subbing in x for w^2, and then using the quadratic on it, then subbing back, and you might get something pretty ugly

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0wolfram alpha should be able to solve it too but i would just use it to compare your results

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0I look at this and it is like Greek to me..I mean I kinda get it, this is where I get confused...

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Alright you take the w^2's and replace them with x's. So you will get x^218x2=0. Now that you have it in the quadratic form which is ax^2+bx+c=0. You can determine the values of a, b, and c. Thus a = 1, b =18, and c =2. With this in mind you apply the quardratic formula which is...\[b \pm \sqrt{b ^{2}4ac}\div 2a\] you simply will now plug in the values of a,b,c that was listed above. You will get 2 answers.. one using the negative b and one using the positive b+. And your done!
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