What is the solution for w: w^4-18w^2-2=0

At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Get our expert's

answer on brainly

SEE EXPERT ANSWER

Get your free account and access expert answers to this and thousands of other questions.

A community for students.

What is the solution for w: w^4-18w^2-2=0

Mathematics
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Get this expert

answer on brainly

SEE EXPERT ANSWER

Get your free account and access expert answers to this and thousands of other questions

http://www.algebra.com/algebra/homework/quadratic/Quadratic_Equations.faq.question.332342.html
yeah, it looks like that one would be best done with subbing in x for w^2, and then using the quadratic on it, then subbing back, and you might get something pretty ugly
wolfram alpha should be able to solve it too but i would just use it to compare your results

Not the answer you are looking for?

Search for more explanations.

Ask your own question

Other answers:

I look at this and it is like Greek to me..I mean I kinda get it, this is where I get confused...
Alright you take the w^2's and replace them with x's. So you will get x^2-18x-2=0. Now that you have it in the quadratic form which is ax^2+bx+c=0. You can determine the values of a, b, and c. Thus a = 1, b =-18, and c =-2. With this in mind you apply the quardratic formula which is...\[-b \pm \sqrt{b ^{2}-4ac}\div 2a\] you simply will now plug in the values of a,b,c that was listed above. You will get 2 answers.. one using the negative -b- and one using the positive -b+. And your done!

Not the answer you are looking for?

Search for more explanations.

Ask your own question