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anonymous

  • 5 years ago

factor 56b2+23b-63 please so in detail how to factor.

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  1. anonymous
    • 5 years ago
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    you need to use quadratic formula for this , because the numbers are far too big to factor it normally

  2. anonymous
    • 5 years ago
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    \[x =\frac{ -b +- \sqrt{b^2-4ac}}{2a}\]

  3. anonymous
    • 5 years ago
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    where a= 56, b=23 and c=-63

  4. anonymous
    • 5 years ago
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    after all that, you get solutions b=-9/7 and b= 7/8 therefore the factorisation is (b - (-9/7) )(b-(7/8))

  5. anonymous
    • 5 years ago
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    = ( 7b+9)(8b-7) after getting over common denominator etc

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