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anonymous

  • 5 years ago

For any positive rational number k, and any real number c, which of the following is incorrect? a.limxaprochinf c = c b limitxaproch-inf. c = c c.limitxaprochinf c/x^k = 0 d.limitxaproch-inf c/x^k = 0 e. All are correct

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  1. myininaya
    • 5 years ago
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    see i already answered this lol

  2. anonymous
    • 5 years ago
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    D!

  3. myininaya
    • 5 years ago
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    no D is true its e

  4. anonymous
    • 5 years ago
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    sory i have corrected choice d can u see it plzzzz?

  5. myininaya
    • 5 years ago
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    yes i see it e is the answer they are all true

  6. anonymous
    • 5 years ago
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    plz can u explain it?

  7. myininaya
    • 5 years ago
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    c in constant it has one value no matter what x is its a horizontal line so didn't doesn't matter what x approaches f(x) will always appoach c since f(x)=c. now what 1/x approach if x approaches infinity?

  8. anonymous
    • 5 years ago
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    Wait, I still think d is false. Think about it, as the denominator goes to -infinity, wouldn't it go to 0. Now 1/0 = infinity

  9. myininaya
    • 5 years ago
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    oh k is rational not an integer so that means if we have 1/(x^(1/2)), then x-> -inf, f wouldn't exist. if k is integer d is true

  10. myininaya
    • 5 years ago
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    no phinx it will go to 0 if the funtion exist for negative numbers

  11. anonymous
    • 5 years ago
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    ohhh, I misread

  12. myininaya
    • 5 years ago
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    but still d is not true since k is rational

  13. anonymous
    • 5 years ago
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    can u plz solve it by steps?

  14. anonymous
    • 5 years ago
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    1 / infinity = 0

  15. anonymous
    • 5 years ago
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    It has to be d) Because, the limit does not exist, x^k does not exist for negative numbers, if k is any rational number

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