anonymous
  • anonymous
For any positive rational number k, and any real number c, which of the following is incorrect? a.limxaprochinf c = c b limitxaproch-inf. c = c c.limitxaprochinf c/x^k = 0 d.limitxaproch-inf c/x^k = 0 e. All are correct
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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jamiebookeater
  • jamiebookeater
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myininaya
  • myininaya
see i already answered this lol
anonymous
  • anonymous
D!
myininaya
  • myininaya
no D is true its e

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anonymous
  • anonymous
sory i have corrected choice d can u see it plzzzz?
myininaya
  • myininaya
yes i see it e is the answer they are all true
anonymous
  • anonymous
plz can u explain it?
myininaya
  • myininaya
c in constant it has one value no matter what x is its a horizontal line so didn't doesn't matter what x approaches f(x) will always appoach c since f(x)=c. now what 1/x approach if x approaches infinity?
anonymous
  • anonymous
Wait, I still think d is false. Think about it, as the denominator goes to -infinity, wouldn't it go to 0. Now 1/0 = infinity
myininaya
  • myininaya
oh k is rational not an integer so that means if we have 1/(x^(1/2)), then x-> -inf, f wouldn't exist. if k is integer d is true
myininaya
  • myininaya
no phinx it will go to 0 if the funtion exist for negative numbers
anonymous
  • anonymous
ohhh, I misread
myininaya
  • myininaya
but still d is not true since k is rational
anonymous
  • anonymous
can u plz solve it by steps?
anonymous
  • anonymous
1 / infinity = 0
anonymous
  • anonymous
It has to be d) Because, the limit does not exist, x^k does not exist for negative numbers, if k is any rational number

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