A community for students.
Here's the question you clicked on:
 0 viewing
anonymous
 5 years ago
A person travelling 6kmph reaches his office 15 min late.Had he travelled at 8kmph, he would have been 25 minutes early. find the distance
anonymous
 5 years ago
A person travelling 6kmph reaches his office 15 min late.Had he travelled at 8kmph, he would have been 25 minutes early. find the distance

This Question is Closed

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0dude kmph and and minutes ... so need to convert ... plz solve

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0t+1/4 = d/6 t5/12 = d/8

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0now i assume u can solve linear eqns

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Let the distance be x Speed =. ( distance / time ) Distance = speed * time 6t + 90 = 8t 200 2t = 290 T =145 t  25 = 120 = 2 hrs 120 + 15 = 135 135/60 * 6 = d D = 13.5 km

dumbcow
 5 years ago
Best ResponseYou've already chosen the best response.0use him1618 equations and solve for d using either substitution or elimination t = d/6  1/4 > (d/6  1/4) 5/12 = d/8

dumbcow
 5 years ago
Best ResponseYou've already chosen the best response.01/4  5/12 = d/8  d/6 3/12 5/12 = 6d/48  8d/48 8/12 = 2d/48 2/3 = d/24 48/3 = d 16 = d
Ask your own question
Sign UpFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.