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anonymous
 5 years ago
A person travelling 6kmph reaches his office 15 min late.Had he travelled at 8kmph, he would have been 25 minutes early. find the distance
anonymous
 5 years ago
A person travelling 6kmph reaches his office 15 min late.Had he travelled at 8kmph, he would have been 25 minutes early. find the distance

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anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0dude kmph and and minutes ... so need to convert ... plz solve

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0t+1/4 = d/6 t5/12 = d/8

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0now i assume u can solve linear eqns

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Let the distance be x Speed =. ( distance / time ) Distance = speed * time 6t + 90 = 8t 200 2t = 290 T =145 t  25 = 120 = 2 hrs 120 + 15 = 135 135/60 * 6 = d D = 13.5 km

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0use him1618 equations and solve for d using either substitution or elimination t = d/6  1/4 > (d/6  1/4) 5/12 = d/8

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.01/4  5/12 = d/8  d/6 3/12 5/12 = 6d/48  8d/48 8/12 = 2d/48 2/3 = d/24 48/3 = d 16 = d
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