## anonymous 5 years ago F(t)=12sint, [0,9π/2]

1. anonymous

what do u want with this?

2. anonymous

?????????

3. anonymous

calculate the avergae value of the function F(t)=12sint, across the interval [0,9π/2] I have the answer but dont understand how to get the end answer

4. anonymous

$=\frac{1}{9\pi/2}12\int\limits_{0}^{9\pi/2}\sin t dt$

5. anonymous

thanks dumb cow :D

6. anonymous

welcome glad that helped its same formula whenever you need avg value

7. anonymous

sweet :D:D:D will be very useful :D