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anonymous

  • 5 years ago

F(t)=12sint, [0,9π/2]

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  1. anonymous
    • 5 years ago
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    what do u want with this?

  2. anonymous
    • 5 years ago
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    ?????????

  3. anonymous
    • 5 years ago
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    calculate the avergae value of the function F(t)=12sint, across the interval [0,9π/2] I have the answer but dont understand how to get the end answer

  4. dumbcow
    • 5 years ago
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    \[=\frac{1}{9\pi/2}12\int\limits_{0}^{9\pi/2}\sin t dt\]

  5. anonymous
    • 5 years ago
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    thanks dumb cow :D

  6. dumbcow
    • 5 years ago
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    welcome glad that helped its same formula whenever you need avg value

  7. anonymous
    • 5 years ago
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    sweet :D:D:D will be very useful :D

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