A community for students.
Here's the question you clicked on:
 0 viewing
anonymous
 5 years ago
complete the following integral or partial substitution with
a. ∫(x^5+2x)/(x^6+6x^2+56)^2 dx
anonymous
 5 years ago
complete the following integral or partial substitution with a. ∫(x^5+2x)/(x^6+6x^2+56)^2 dx

This Question is Closed

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0∫(x^5+2x)/(x^6+6x^2+56)^2 dx ∫(x^5+2x) dx  ∫(x^6+6x^2+56)^2 dx

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0You can't do this in products, only in additions. suzi20

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0u = x^6 +6x^2 +56 du = 6x^5 +12x dx du = 6(x^5 +2x) dx

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0dv = (x^6+6x^2+56)^2 dx v = 1 (x^6+6x^2+56)^1 uv  ∫ v du (x^6 +6x^2 +56)((x^6+6x^2+56)^1)  1/6∫((x^6+6x^2+56)^1) (x^5 +2x) dx hmm... hard

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Suzi please continue the answer

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0u have to do partial again

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Let x^6 + 6x^2 + 56 = t Now, du = 6x^5 + 12x dx = 6(x^5 + 2x) dx The integral becomes, \[1/6\int\limits_{}{}dt/t^2\] \[1/6t\] Putting back the value of t = 1/6(x^6+6x^2+56)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0I could ask you to complete

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0that's calculus 2, i remember now, wow amogh cool...........

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0amogh can I ask you to write down the answer from the first until the end if you're willing I will be very thankful to you

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Tell me what you didn't understand, I've written it completely!

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0oh I'm sorry, I really do not understand about the calculus lesson, but I want to learn

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Let x^6 + 6x^2 + 56 = t Differentiating on both sides, Now, dt = (6x^5 + 12x)dx = 6(x^5 + 2x) dx Multiplying the integral by 6 and diving by 6, \[1/6\int\limits_{}^{}6(x^5+2x)/(x^6+6x^2+56)^2 dx\] Now 6(x^5+2x) becomes dt. The integral becomes, \[1/6\int\limits_{}^{} dt/t^2\] = −1/6t Putting back the value of t = 1/6(x^6+6x^2+56)
Ask your own question
Sign UpFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.