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anonymous
 5 years ago
∫sin^2x/cos^4x dx
anonymous
 5 years ago
∫sin^2x/cos^4x dx

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anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0sin^2 + cos^2 =1 tan^2 + 1 = sec^2

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0so integrad becomes sec^2(x) [ sec^2 (x) 1 ]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0expanding sec^4(x) sec^2(x) , now sec^2 integrals to tan so we look to rewrite the sec^4(x)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Thank you but how can i rewrite sec^4(x)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0yeh , by checking with wolframa " http://www.wolframalpha.com/input/?i=xtan%28x%29 " there is no way to do this with only elementary functions

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0your teacher shouldnt be asking you to do this question

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0if a software package has trouble doing it then how can they expect a student to do it

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0This question was in my book the answer is 1/3tan^3(x) but hhats all they've wrote

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0when you get to tan^2(x)sec^2(x) you do a substittuion, u= tan(x) so du= sec^2(x) dx

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0so you get the integral of u^2 du , which gives the answer
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