anonymous
  • anonymous
calculate plane equation (1,0,0), (0,1,0),(0,0,1)
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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jamiebookeater
  • jamiebookeater
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amistre64
  • amistre64
yay.... given three point we can create 2 vectors and cross product for the noral right?
anonymous
  • anonymous
yes. but please do it. i'm being too lazy =P
amistre64
  • amistre64
LOL.... happy to, i need the practice ;)

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amistre64
  • amistre64
lets choose a starting point; (1,0,0) looks fine; and create a vector from that point another and then the other
anonymous
  • anonymous
cheers!
amistre64
  • amistre64
(1,0,0) (0,1,0) ------- <1,1,0> = v1 (1,0,0) (0,0,1) ------ <1,0,1> = v2 right?
amistre64
  • amistre64
we cross these 2 vectors to get a normal vector to the plane: < i, j, k> <1,1,0> <1,0,1> ---------- +(1-0) | - (1-0) | = <1,1,-1> for the normal +(0-1) |
anonymous
  • anonymous
just the pane eq...
amistre64
  • amistre64
now attach the normal to a point... once you fix my typo lol <1,-1,-1> = n ; and P(1,0,0) 1(x-1) -1(y+0) -1(z+0) = 0
amistre64
  • amistre64
x-1 -y -z = 0 x-y-z-1 = 0 should satisfy it
amistre64
  • amistre64
i wonder if i did my point addition right...
anonymous
  • anonymous
thanks alot1 =)
amistre64
  • amistre64
was it correct?
anonymous
  • anonymous
i dunno =P its part of a long question.
amistre64
  • amistre64
well, let me dbl check me thoughts and verify my results :)
anonymous
  • anonymous
yes plz =)
anonymous
  • anonymous
it correct! thumbs up!
amistre64
  • amistre64
yay!! ..... i was like 84% sure :)
anonymous
  • anonymous
x+y+z-1=0 the normal vector shd be 1,1,1. Use intuition. If you want to use the cross product to find the normal vector, it shd be: (1,-1,0)×(0,1,-1)=(1,1,1). Bear in mind that you should subtract one vector from another, NOT add them together. The next step should be verifying your answer, in this case, try sub. (1,0,0), (0,1,0), (0,0,1) into your equation to see if it makes sense.
amistre64
  • amistre64
thats what my doubts were :) I saw that in the back of my head ..
amistre64
  • amistre64
but i couldnt seem to get the crossproduct of the vectors; even with subtraction; to conform...
amistre64
  • amistre64
(1,0,0) (1,0,0) -(0,1,0) -(0,0,1) ------- ------ <1,-1,0> <1,0,-1> <1,-1,0> <1,0,-1> <1-0,-(-1-0),0-1> = <1,1,-1>
amistre64
  • amistre64
1(x-1) +1(y+0)-1(z+0) = 0 x + y -z -1 = 0 ....
amistre64
  • amistre64
(0,0,1) = -2 then
anonymous
  • anonymous
So the true answer is x+y+z=1 for your k component in the post 4 min ago, it should be (0)(1)-(-1)(1)=1
amistre64
  • amistre64
.... i forgot how to multiply lol....
anonymous
  • anonymous
^.^ Are you from USA?
amistre64
  • amistre64
I am
amistre64
  • amistre64
i kept breezing over that k part and needed a 2nd set of eyes to overcome my inherent stupidity :) thanx..
anonymous
  • anonymous
"add oil" Guess from where I come from.
amistre64
  • amistre64
venezula?
amistre64
  • amistre64
cape fear?
amistre64
  • amistre64
madagascar... gotta be madagascar :)
anonymous
  • anonymous
no =] it should not be hard to guess if you google "add oil"
amistre64
  • amistre64
its cantonese; soo... you from canton?
anonymous
  • anonymous
Hong kong actually
anonymous
  • anonymous
so add oil
amistre64
  • amistre64
thnx :) you too

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