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anonymous
 5 years ago
calculate plane equation (1,0,0), (0,1,0),(0,0,1)
anonymous
 5 years ago
calculate plane equation (1,0,0), (0,1,0),(0,0,1)

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amistre64
 5 years ago
Best ResponseYou've already chosen the best response.1yay.... given three point we can create 2 vectors and cross product for the noral right?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0yes. but please do it. i'm being too lazy =P

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.1LOL.... happy to, i need the practice ;)

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.1lets choose a starting point; (1,0,0) looks fine; and create a vector from that point another and then the other

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.1(1,0,0) (0,1,0)  <1,1,0> = v1 (1,0,0) (0,0,1)  <1,0,1> = v2 right?

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.1we cross these 2 vectors to get a normal vector to the plane: < i, j, k> <1,1,0> <1,0,1>  +(10)   (10)  = <1,1,1> for the normal +(01) 

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.1now attach the normal to a point... once you fix my typo lol <1,1,1> = n ; and P(1,0,0) 1(x1) 1(y+0) 1(z+0) = 0

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.1x1 y z = 0 xyz1 = 0 should satisfy it

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.1i wonder if i did my point addition right...

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0i dunno =P its part of a long question.

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.1well, let me dbl check me thoughts and verify my results :)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0it correct! thumbs up!

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.1yay!! ..... i was like 84% sure :)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0x+y+z1=0 the normal vector shd be 1,1,1. Use intuition. If you want to use the cross product to find the normal vector, it shd be: (1,1,0)×(0,1,1)=(1,1,1). Bear in mind that you should subtract one vector from another, NOT add them together. The next step should be verifying your answer, in this case, try sub. (1,0,0), (0,1,0), (0,0,1) into your equation to see if it makes sense.

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.1thats what my doubts were :) I saw that in the back of my head ..

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.1but i couldnt seem to get the crossproduct of the vectors; even with subtraction; to conform...

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.1(1,0,0) (1,0,0) (0,1,0) (0,0,1)   <1,1,0> <1,0,1> <1,1,0> <1,0,1> <10,(10),01> = <1,1,1>

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.11(x1) +1(y+0)1(z+0) = 0 x + y z 1 = 0 ....

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0So the true answer is x+y+z=1 for your k component in the post 4 min ago, it should be (0)(1)(1)(1)=1

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.1.... i forgot how to multiply lol....

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0^.^ Are you from USA?

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.1i kept breezing over that k part and needed a 2nd set of eyes to overcome my inherent stupidity :) thanx..

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0"add oil" Guess from where I come from.

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.1madagascar... gotta be madagascar :)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0no =] it should not be hard to guess if you google "add oil"

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.1its cantonese; soo... you from canton?
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