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anonymous
 5 years ago
Solve this equation on the interval 0\[\le\] θ < 2π. If there is only one solution, write it in the upper box and write NONE in the lower box. If there is no solution, write NONE in both boxes.
Round your answer(s) to two decimal places using radians.
θ = (smaller value of θ)
θ = (larger value of θ)
anonymous
 5 years ago
Solve this equation on the interval 0\[\le\] θ < 2π. If there is only one solution, write it in the upper box and write NONE in the lower box. If there is no solution, write NONE in both boxes. Round your answer(s) to two decimal places using radians. θ = (smaller value of θ) θ = (larger value of θ)

This Question is Closed

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.1there is no equation here...

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0haha really? why is that?

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.1Its alot of instructions on what to do; but there is no equation to work it on lol

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0sintheta + sqrt3costheta = 1

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.1sin(t) + sqrt(3)cos(t) = 1 right?

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.1then.... sqrt(3)cos(t) = 1  sin(t) 3cos^2 = 1 +sin^2 2sin... lets cheat and do this lol http://www.wolframalpha.com/input/?i=sin%28t%29+%2B+sqrt%283%29cos%28t%29+%3D+1

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0hahaha thats the way!

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0damn it im not gettin it!

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.1i cant seem to get it out either.... i know theres one answer at least; might have to just make a chart and narrow it in

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0http://www.wolframalpha.com/input/?i=Solve%5Bsin%28t%29+%2B+sqrt%283%29cos%28t%29+%3D%3D+1%2Ct%5D

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.1an alternative form is: \[4\sin[\frac{\pi}{4}\frac{t}{2}] . \sin[\frac{t}{2}+\frac{\pi}{12}]=0\]

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.1since sin = 0 at 0 and pi; we can prolly figure out a few t's from this ?

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.1t/2 = pi/4 t = pi/2sounds reasoneable plug it into the orifinal and test

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0i think ur getin somewhere haha

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.1the other seems to be pi/6 but that aint in the inteval is it lol

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.1sin(pi / 2) + (sqrt(3) * cos(pi / 2)) = 1 is good tho

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0would that be the lower value or upper value?

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.1thats the lower value

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0i only get two shots so i probably beta wait till we figur out the upper value lol

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.1its close to 2pi according to the graph

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.1now we know pi/6 is good; but if we take and try to reach that going from 0 to 2pi what do we get? i wonder

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.1sin((11 * pi) / 6) + (sqrt(3) * cos((11 * pi) / 6)) = 1: from google

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.1all angles have many names to them because when you walk around a circle you can go along way and still get nowhere

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.1we can walk pi/6 to smell the roses; or we can take the long way around; and walk 11pi/6 to get to the same place to wmell the roses

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0lol. so u added two pi?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0haha. it works doesnt it?

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.1it does indeed :) becuase they both have the same values

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0kay so u reckon i should give pi/2 and 11pi/6 a shot?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0yay ur a genius!!! it works haha

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.1lol .... i had to remember my trigs :)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0haha. is there a simpler way of doing this tho?

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.1i caouldnt find a way to get it into the alternate form; but wolfram did... so i tested that forms results into the original and they worked like a charm

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0so are you a teacher?

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.1no, just old :) im trying to get my masters degree in math tho so I can teach college math

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0good effort. you'll get there mate haha
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