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anonymous
 5 years ago
A sphere of mass 50gm and radius 10cm rolls without slipping with a velocity of 5cm/s.
Its total kinetic energy in ergs is?
anonymous
 5 years ago
A sphere of mass 50gm and radius 10cm rolls without slipping with a velocity of 5cm/s. Its total kinetic energy in ergs is?

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anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0KE = translational KE + rotational KE. So translational KE is 1/2mv^2. Rotational KE is 1/2Iw^2. I is the moment of inertia for a solid sphere.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0I think it may need a bit more...maybe not but oh well there are some ideas missing here...the moment of inertia of a sphere is I=mr^2 and the angular velocity is going to be the 5cm/s divided by the radius. Those are going to be need to calculate better...I hope I wasnt going too deep http://mathphystut.tripod.com

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0the moment of inertia of a sphere is I=2/5mr^2 you might wanna check that

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0ooo...nice call...you a head cracker deeprony

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0thanx for the heads up...i dont know how I messed that one up

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0no worries. happens to the best of all...=)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0hey can you help me with this one, If (2,8) is the coordinates of an end point of a focal chord of y^2=4ax, then the coordinates of the other end are?
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