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simple harmonic i believe; there is no part of it that is accounting for a dampned effect
1 is the max displacement
the displacement from rest is the amplitude; which is 1 the initial displacement tho is -1
it asks for decimal places tho?
initial disp is 0 amistre
1.0000 then lol
well.... yeah, initial = 0 :)
1/18pi is the frequency
and hence18pi is the time period for one oscillation
so max disp is 0 or 1?
are you accounting for the pi already in the problem? or are you atributing an external pi?
see the eqn for shm is x=sin (wt)
lol i got lost
w=1/9 hence f = 1/18pi
i get turned around whe w = pi/n lol
and since T=1/f , T=18pi
http://www.wolframalpha.com/input/?i=-sin%28t%2F9%29 hims good on it
yeah waves were my forte ;)
so was c) 18pi ?
did u follow the working?
lol got lost
would you mind explaining it to me?
do u know what simple harmonic motion is?
i did it before but forgot. is it got to do with the pendulums?
yeah...anything in shm follows the displacement eqn x = Asin(wt) w is called the angular frequency and equals 2pi x f where f is the frequency
and f=1/T where T is the time for one cycle or oscillation
i remember now haha
max disp from its resting position isnt 1 tho
im not sure. but the answer u got is 1.00? its not right for some reason
so its -1?
is it -1.00??
must be that then...
no it isn't.
it must be to two dp and be in meters
gotta be 1.00...dunno y its coming out wrong..
me either but it aint working. tried it already
cud it be 0
how do u work that part anyways?
hey amistre, the max disp from rest is turnin out wrong
i put in -1.00 and 1.00 both r wrong
thats becasue we assumed displacement = amplitude d = displacement; so we gotta work the formula :)
amplitude is defined as the max displacemnt from the mean position
it peaks at |+-1| it aint asking for the value of 't' at the max becasue there aint no interval to associate a single t into
have you tried it without the decimals?
just enter: 1
its my last shot tho lol
nah, it didnt work