## anonymous 5 years ago hey, sorry about going off subject, i would like to ask a question on physics. Since there isn't anyone in that section i am helpless. here is my question: A cylinder of radius 20cm and mass 100g rolls down an inclined plane of height 60cm without slipping. the linear velocity of the cylinder at the bottom is?? (g=980cm/s/s)

1. anonymous

mgh = KE

2. anonymous

1/2 mv^2+1/2 I w^2= Mgh

3. anonymous

i did that but i m not gettin the answer.

4. anonymous

KE = KE(r) + KE(t) 1/2(mr^2/2)w^2 + 1/2 x m x v^2

5. anonymous

rw=v w=v/r substitute

6. anonymous

3/4 x mv^2 = mgh

7. anonymous

i went through all that buddy. can you solve ang post your anser.

8. anonymous

9. anonymous

v=2.8 m/s

10. anonymous

ow rats! i made a calculation mistake! neway thnx buddy..

11. anonymous

no prob

12. anonymous

wat is the radius of curveture if a particle moves in a trajectory given by y=f(x) at any point(x,y)

13. anonymous

parameterize the eqn in terms of time....r =v^2/a(radial)

14. anonymous

it is given as $R=[1+(dy/dx)^{2}\left[ \right]^{3/2}$

15. anonymous

divied by d^2y\dx^2

16. anonymous

if u know the answer then y do u ask..i dont memorize formulae..its wiser to go through the basic approach...

17. anonymous

i want to kno how it came