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anonymous
 5 years ago
y=(tan(x))^arcsin(x) , whats dy/x ?
Wont this be d(tan(x)^arcsin(x))/dtan(x) * d(tan(x))/dx according to the chain rule ?
Where am I going wrong?
anonymous
 5 years ago
y=(tan(x))^arcsin(x) , whats dy/x ? Wont this be d(tan(x)^arcsin(x))/dtan(x) * d(tan(x))/dx according to the chain rule ? Where am I going wrong?

This Question is Closed

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0to simply this take ln on both sides

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0\[y=\tan(x)^{\arcsin(x)}\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0ln y = arcsinx (ln tanx)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0What's wrong with what I said about the chain rule ?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0ur doing it wrong..its complicated..if u want it that way u treat one fn as constant and then diff and add it to the derivative keeping second fn constant

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0like if uv got f(x) and g(x) and y=f^g dy/dx = gf^(g1) + (lnf)f^g

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Getting confused. Dont understand why I need to add functions here.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0dy/dx = gf^(g1) + (lnf)f^g makes it to add ..

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0but can you tell me whats wrong with the chain rule ? am afraid I have not understood the chain rule itself properly cause of it got wrong.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0f(x)=h(g(x)) , f'(x) = h'(g(x))*g'(x) , is this not what I did too ?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0derivative of outside function w.r.t its argument * derivative of argument w.r.t independent variable

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0u know it right..but here we cannot use the chain rule

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0u tell me...r u in class 12?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0why cant I use chain rule here ?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0for using the chain rule for sin(e^x) do u need to know the derivative of sinx or not?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0ur thinking of simpler derivatives for the chain rule..for eg we know a^x ka derivative...so hencewe can derive a^f(x)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0wont that be cos(e^x) * e^x ?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0yes...just an example..the thing is that there is no standard derivative of tanx ^x

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0ur treating ur function as f(g(x)) where f is tanx and g is arcsinx which is wrong

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0yes am treating it like that , why is it wrong ??

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0agar aisa hota to it wldve been tan (arcsinx) or something

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0acha , see this , how do you differenciate x^x w.r.t x then ?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0cz remember in a composite fn in place of X there is another function, here theres no function in place of x itself na? do u c?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0so u do logarithmic differentiation or u maro style and keep one fn constant and do that pellet...right...?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0thing is I have not yet come to logarithmic differentiation abhi tak ... all I know is chain rule

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0I can blindly convince myself that I might need logarithmic differentiation for this , but I truly dont understand why chain rule cant do.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0this is only an extension of chain rule..bt ive taught u now havent i whenever u c exponents like y=f^g take log on both sides and then u can apply chain rule

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0this is a chain rule question...just gotta use brains and log properties

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0is it like when g and f are 2 functions of x and h is another function = g^f , you need to use logarithmic ?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0see y = x^sinx ln y= sinxlnx now use chain rule

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0thanks a lot..u gave me something to think abt...mazaa aagaya..bt dont think m nerdy...

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0yes .. ;) lol no problems , what do you do ?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0ive given iit right one month back...

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0hey him1618, i think chain rule can suffice ... no log needed

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Like you were in 12th and gave IIT or just gave IIT being elder?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0abhi 12th pass ki hai yyar..beizzati mat karo

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0i passed in 2011..gave iit in 2011

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0fine fine wrote AIEEE?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0thanx...aakash sahib kahan gaye...

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0yeah..but marks nahi lagaye..wanted to be free

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Aakash went to temple .. will be right back soon he says.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Are you on any IM ? What's your gtalk ?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0facebook...u in delhi?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0k.....add Himanish...studied at St. Columba's School

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0ur pretty...g2g...ill add u

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0thanks haha :) , sure.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0hey him... sorry .. now i realize my mistake .. u r rite ... we need to find the derivative of x^arcsin(x) and then multiply with diff of tan (x^arcsin(x))

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0we find the first one using log .. as u said

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0dont pste ur fb id on public pages....aakash....sk goyal ke phatte aise hi nhi maare..bye

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Damn posted my fb profile here !

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0toldya..b careful next tym

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0mean do u go fr quizzes and all?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0yeah..i am..just inquiring whether uve heard of the columban open quiz...nvm...ive sent u d request

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0btw what are you planning to study next after 12th ?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0engineering physics btech

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Oh , which university ?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0abhi result to aane do yaar..waise i think ill get into one of the IITs

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Was IIT easy this year ?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0How many hours do you study for IIT ? Went to any coaching ?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0yes..only i screwed up...

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0narayana...no defined hours of study...

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0went to any coaching classes at narayana or you stay at narayana ?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0assuming you mean "narayna" the area ..

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Oh , wait i'll add now.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0how do you get an area under a function f(x) between spans x=a and x=b when you integrate it ?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0How come it fetches you the area ? intuition behind it ?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0u divide the area under the graph into small strips along the xaxis, each having width dx

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Dude , gimme an IM. I cant login to facebook right now , my sis's logged in and if I log out , she'll scream , its her laptop. Give me your google talk or msn or yahoo or AIM or skype or whatever.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0these rectangular strips have height f(x) at point x, and width dx no IM now...my bits is on monday..sm1 sees m dead...

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0now area is the summation of all these small areas

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0\[A =\lim_{dx \rightarrow 0} \sum_{a}^{b}f(x)dx = \int\limits_{b}^{a}f(x)dx\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0u cn call me if u want...m free after monday...only if ur comfortable with it

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0I will definitely call you on mind , if you dont mind getting disturbed.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0after monday..no disturbance frm gorgeous ppl...;)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0ill msg my no on fb kal dekhlena

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0;) sure. I understood the intuition somewhat now , cool. thanks

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0no prob mis...ek din derivative bhi samjhaaoonga..bye g2g

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Not really , I think its too late now ? I never went to any coaching or prepared with IIT point of view.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0k..to yeh dabanng question kahaan se laye the?i think ur mind works in the right way..90 pc people don t even think abt d meaning f an integral

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0lol really ? well I was just trying to understand how that works.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Trust me yaar , am weak at maths. I dont do well at all.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0waise india ka education system is bakwas

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Alright , surely will call you Mr. Brains.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0just browsing. YouTube.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0You heard of Manipal ?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0university?my pals giving the exam tomorrow

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Yes. You dont have plans for that? I heard its good?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Where is it actually?
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