anonymous
  • anonymous
y=(tan(x))^arcsin(x) , whats dy/x ? Wont this be d(tan(x)^arcsin(x))/dtan(x) * d(tan(x))/dx according to the chain rule ? Where am I going wrong?
Mathematics
  • Stacey Warren - Expert brainly.com
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schrodinger
  • schrodinger
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anonymous
  • anonymous
to simply this take ln on both sides
anonymous
  • anonymous
\[y=\tan(x)^{\arcsin(x)}\]
anonymous
  • anonymous
ln y = arcsinx (ln tanx)

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anonymous
  • anonymous
What's wrong with what I said about the chain rule ?
anonymous
  • anonymous
ur doing it wrong..its complicated..if u want it that way u treat one fn as constant and then diff and add it to the derivative keeping second fn constant
anonymous
  • anonymous
like if uv got f(x) and g(x) and y=f^g dy/dx = gf^(g-1) + (lnf)f^g
anonymous
  • anonymous
Getting confused. Dont understand why I need to add functions here.
anonymous
  • anonymous
Oh
anonymous
  • anonymous
now u get it?
anonymous
  • anonymous
dy/dx = gf^(g-1) + (lnf)f^g makes it to add ..
anonymous
  • anonymous
but can you tell me whats wrong with the chain rule ? am afraid I have not understood the chain rule itself properly cause of it got wrong.
anonymous
  • anonymous
f(x)=h(g(x)) , f'(x) = h'(g(x))*g'(x) , is this not what I did too ?
anonymous
  • anonymous
derivative of outside function w.r.t its argument * derivative of argument w.r.t independent variable
anonymous
  • anonymous
u know it right..but here we cannot use the chain rule
anonymous
  • anonymous
u tell me...r u in class 12?
anonymous
  • anonymous
yes am in class 12
anonymous
  • anonymous
why cant I use chain rule here ?
anonymous
  • anonymous
for using the chain rule for sin(e^x) do u need to know the derivative of sinx or not?
anonymous
  • anonymous
yes I know
anonymous
  • anonymous
ur thinking of simpler derivatives for the chain rule..for eg we know a^x ka derivative...so hencewe can derive a^f(x)
anonymous
  • anonymous
wont that be cos(e^x) * e^x ?
anonymous
  • anonymous
yes...just an example..the thing is that there is no standard derivative of tanx ^x
anonymous
  • anonymous
ur treating ur function as f(g(x)) where f is tanx and g is arcsinx which is wrong
anonymous
  • anonymous
yes am treating it like that , why is it wrong ??
anonymous
  • anonymous
agar aisa hota to it wldve been tan (arcsinx) or something
anonymous
  • anonymous
acha , see this , how do you differenciate x^x w.r.t x then ?
anonymous
  • anonymous
cz remember in a composite fn in place of X there is another function, here theres no function in place of x itself na? do u c?
anonymous
  • anonymous
right
anonymous
  • anonymous
so u do logarithmic differentiation or u maro style and keep one fn constant and do that pellet...right...?
anonymous
  • anonymous
thing is I have not yet come to logarithmic differentiation abhi tak ... all I know is chain rule
anonymous
  • anonymous
I can blindly convince myself that I might need logarithmic differentiation for this , but I truly dont understand why chain rule cant do.
anonymous
  • anonymous
this is only an extension of chain rule..bt ive taught u now havent i whenever u c exponents like y=f^g take log on both sides and then u can apply chain rule
anonymous
  • anonymous
yes
anonymous
  • anonymous
this is a chain rule question...just gotta use brains and log properties
anonymous
  • anonymous
is it like when g and f are 2 functions of x and h is another function = g^f , you need to use logarithmic ?
anonymous
  • anonymous
yeah
anonymous
  • anonymous
see y = x^sinx ln y= sinxlnx now use chain rule
anonymous
  • anonymous
r u in delhi??
anonymous
  • anonymous
thanks a lot..u gave me something to think abt...mazaa aagaya..bt dont think m nerdy...
anonymous
  • anonymous
yes .. ;) lol no problems , what do you do ?
anonymous
  • anonymous
ive given iit right one month back...
anonymous
  • anonymous
hey him1618, i think chain rule can suffice ... no log needed
anonymous
  • anonymous
how?
anonymous
  • anonymous
Like you were in 12th and gave IIT or just gave IIT being elder?
anonymous
  • anonymous
abhi 12th pass ki hai yyar..beizzati mat karo
anonymous
  • anonymous
i passed in 2011..gave iit in 2011
anonymous
  • anonymous
lol you are brainy
anonymous
  • anonymous
fine fine wrote AIEEE?
anonymous
  • anonymous
thanx...aakash sahib kahan gaye...
anonymous
  • anonymous
yeah..but marks nahi lagaye..wanted to be free
anonymous
  • anonymous
Aakash went to temple .. will be right back soon he says.
anonymous
  • anonymous
Are you on any IM ? What's your gtalk ?
anonymous
  • anonymous
facebook...u in delhi?
anonymous
  • anonymous
yes I am in Delhi.
anonymous
  • anonymous
You ?
anonymous
  • anonymous
wt school?
anonymous
  • anonymous
Springdales
anonymous
  • anonymous
you ?
anonymous
  • anonymous
k.....add Himanish...studied at St. Columba's School
anonymous
  • anonymous
http://www.facebook.com/profile.php?id=100002411313746
anonymous
  • anonymous
ur pretty...g2g...ill add u
anonymous
  • anonymous
thanks haha :) , sure.
anonymous
  • anonymous
hey him... sorry .. now i realize my mistake .. u r rite ... we need to find the derivative of x^arcsin(x) and then multiply with diff of tan (x^arcsin(x))
anonymous
  • anonymous
we find the first one using log .. as u said
anonymous
  • anonymous
dont pste ur fb id on public pages....aakash....sk goyal ke phatte aise hi nhi maare..bye
anonymous
  • anonymous
hun?
anonymous
  • anonymous
Damn posted my fb profile here !
anonymous
  • anonymous
toldya..b careful next tym
anonymous
  • anonymous
r u a quizzer?
anonymous
  • anonymous
quizzer ?
anonymous
  • anonymous
what do you mean ?
anonymous
  • anonymous
mean do u go fr quizzes and all?
anonymous
  • anonymous
No , you ?
anonymous
  • anonymous
yeah..i am..just inquiring whether uve heard of the columban open quiz...nvm...ive sent u d request
anonymous
  • anonymous
what request ?
anonymous
  • anonymous
btw what are you planning to study next after 12th ?
anonymous
  • anonymous
engineering physics btech
anonymous
  • anonymous
Oh , which university ?
anonymous
  • anonymous
abhi result to aane do yaar..waise i think ill get into one of the IITs
anonymous
  • anonymous
very nice.
anonymous
  • anonymous
Was IIT easy this year ?
anonymous
  • anonymous
How many hours do you study for IIT ? Went to any coaching ?
anonymous
  • anonymous
yes..only i screwed up...
anonymous
  • anonymous
narayana...no defined hours of study...
anonymous
  • anonymous
went to any coaching classes at narayana or you stay at narayana ?
anonymous
  • anonymous
assuming you mean "narayna" the area ..
anonymous
  • anonymous
narayana iit academy
anonymous
  • anonymous
Oh
anonymous
  • anonymous
hav u added?
anonymous
  • anonymous
Oh , wait i'll add now.
anonymous
  • anonymous
hey
anonymous
  • anonymous
how do you get an area under a function f(x) between spans x=a and x=b when you integrate it ?
anonymous
  • anonymous
How come it fetches you the area ? intuition behind it ?
anonymous
  • anonymous
no..
anonymous
  • anonymous
No ?
anonymous
  • anonymous
u divide the area under the graph into small strips along the x-axis, each having width dx
anonymous
  • anonymous
Dude , gimme an IM. I cant login to facebook right now , my sis's logged in and if I log out , she'll scream , its her laptop. Give me your google talk or msn or yahoo or AIM or skype or whatever.
anonymous
  • anonymous
these rectangular strips have height f(x) at point x, and width dx no IM now...my bits is on monday..sm1 sees m dead...
anonymous
  • anonymous
lol
anonymous
  • anonymous
so dA = f(x)dx
anonymous
  • anonymous
now area is the summation of all these small areas
anonymous
  • anonymous
\[A =\lim_{dx \rightarrow 0} \sum_{a}^{b}f(x)dx = \int\limits_{b}^{a}f(x)dx\]
anonymous
  • anonymous
get it now?
anonymous
  • anonymous
u cn call me if u want...m free after monday...only if ur comfortable with it
anonymous
  • anonymous
samajh aaya?
anonymous
  • anonymous
wait reading
anonymous
  • anonymous
I will definitely call you on mind , if you dont mind getting disturbed.
anonymous
  • anonymous
*monday not mind lol
anonymous
  • anonymous
after monday..no disturbance frm gorgeous ppl...;)
anonymous
  • anonymous
ill msg my no on fb kal dekhlena
anonymous
  • anonymous
;) sure. I understood the intuition somewhat now , cool. thanks
anonymous
  • anonymous
no prob mis...ek din derivative bhi samjhaaoonga..bye g2g
anonymous
  • anonymous
sure
anonymous
  • anonymous
bye
anonymous
  • anonymous
u preparing for iit?
anonymous
  • anonymous
Not really , I think its too late now ? I never went to any coaching or prepared with IIT point of view.
anonymous
  • anonymous
k..to yeh dabanng question kahaan se laye the?i think ur mind works in the right way..90 pc people don t even think abt d meaning f an integral
anonymous
  • anonymous
lol really ? well I was just trying to understand how that works.
anonymous
  • anonymous
Trust me yaar , am weak at maths. I dont do well at all.
anonymous
  • anonymous
waise india ka education system is bakwas
anonymous
  • anonymous
i msgd u my number
anonymous
  • anonymous
Alright , surely will call you Mr. Brains.
anonymous
  • anonymous
so wtr u doing now?
anonymous
  • anonymous
just browsing. YouTube.
anonymous
  • anonymous
You heard of Manipal ?
anonymous
  • anonymous
university?my pals giving the exam tomorrow
anonymous
  • anonymous
Yes. You dont have plans for that? I heard its good?
anonymous
  • anonymous
Where is it actually?
anonymous
  • anonymous
in the south .. good

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