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anonymous

  • 5 years ago

y=(tan(x))^arcsin(x) , whats dy/x ? Wont this be d(tan(x)^arcsin(x))/dtan(x) * d(tan(x))/dx according to the chain rule ? Where am I going wrong?

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  1. anonymous
    • 5 years ago
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    to simply this take ln on both sides

  2. anonymous
    • 5 years ago
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    \[y=\tan(x)^{\arcsin(x)}\]

  3. anonymous
    • 5 years ago
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    ln y = arcsinx (ln tanx)

  4. anonymous
    • 5 years ago
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    What's wrong with what I said about the chain rule ?

  5. anonymous
    • 5 years ago
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    ur doing it wrong..its complicated..if u want it that way u treat one fn as constant and then diff and add it to the derivative keeping second fn constant

  6. anonymous
    • 5 years ago
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    like if uv got f(x) and g(x) and y=f^g dy/dx = gf^(g-1) + (lnf)f^g

  7. anonymous
    • 5 years ago
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    Getting confused. Dont understand why I need to add functions here.

  8. anonymous
    • 5 years ago
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    Oh

  9. anonymous
    • 5 years ago
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    now u get it?

  10. anonymous
    • 5 years ago
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    dy/dx = gf^(g-1) + (lnf)f^g makes it to add ..

  11. anonymous
    • 5 years ago
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    but can you tell me whats wrong with the chain rule ? am afraid I have not understood the chain rule itself properly cause of it got wrong.

  12. anonymous
    • 5 years ago
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    f(x)=h(g(x)) , f'(x) = h'(g(x))*g'(x) , is this not what I did too ?

  13. anonymous
    • 5 years ago
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    derivative of outside function w.r.t its argument * derivative of argument w.r.t independent variable

  14. anonymous
    • 5 years ago
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    u know it right..but here we cannot use the chain rule

  15. anonymous
    • 5 years ago
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    u tell me...r u in class 12?

  16. anonymous
    • 5 years ago
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    yes am in class 12

  17. anonymous
    • 5 years ago
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    why cant I use chain rule here ?

  18. anonymous
    • 5 years ago
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    for using the chain rule for sin(e^x) do u need to know the derivative of sinx or not?

  19. anonymous
    • 5 years ago
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    yes I know

  20. anonymous
    • 5 years ago
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    ur thinking of simpler derivatives for the chain rule..for eg we know a^x ka derivative...so hencewe can derive a^f(x)

  21. anonymous
    • 5 years ago
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    wont that be cos(e^x) * e^x ?

  22. anonymous
    • 5 years ago
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    yes...just an example..the thing is that there is no standard derivative of tanx ^x

  23. anonymous
    • 5 years ago
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    ur treating ur function as f(g(x)) where f is tanx and g is arcsinx which is wrong

  24. anonymous
    • 5 years ago
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    yes am treating it like that , why is it wrong ??

  25. anonymous
    • 5 years ago
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    agar aisa hota to it wldve been tan (arcsinx) or something

  26. anonymous
    • 5 years ago
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    acha , see this , how do you differenciate x^x w.r.t x then ?

  27. anonymous
    • 5 years ago
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    cz remember in a composite fn in place of X there is another function, here theres no function in place of x itself na? do u c?

  28. anonymous
    • 5 years ago
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    right

  29. anonymous
    • 5 years ago
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    so u do logarithmic differentiation or u maro style and keep one fn constant and do that pellet...right...?

  30. anonymous
    • 5 years ago
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    thing is I have not yet come to logarithmic differentiation abhi tak ... all I know is chain rule

  31. anonymous
    • 5 years ago
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    I can blindly convince myself that I might need logarithmic differentiation for this , but I truly dont understand why chain rule cant do.

  32. anonymous
    • 5 years ago
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    this is only an extension of chain rule..bt ive taught u now havent i whenever u c exponents like y=f^g take log on both sides and then u can apply chain rule

  33. anonymous
    • 5 years ago
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    yes

  34. anonymous
    • 5 years ago
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    this is a chain rule question...just gotta use brains and log properties

  35. anonymous
    • 5 years ago
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    is it like when g and f are 2 functions of x and h is another function = g^f , you need to use logarithmic ?

  36. anonymous
    • 5 years ago
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    yeah

  37. anonymous
    • 5 years ago
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    see y = x^sinx ln y= sinxlnx now use chain rule

  38. anonymous
    • 5 years ago
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    r u in delhi??

  39. anonymous
    • 5 years ago
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    thanks a lot..u gave me something to think abt...mazaa aagaya..bt dont think m nerdy...

  40. anonymous
    • 5 years ago
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    yes .. ;) lol no problems , what do you do ?

  41. anonymous
    • 5 years ago
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    ive given iit right one month back...

  42. anonymous
    • 5 years ago
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    hey him1618, i think chain rule can suffice ... no log needed

  43. anonymous
    • 5 years ago
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    how?

  44. anonymous
    • 5 years ago
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    Like you were in 12th and gave IIT or just gave IIT being elder?

  45. anonymous
    • 5 years ago
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    abhi 12th pass ki hai yyar..beizzati mat karo

  46. anonymous
    • 5 years ago
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    i passed in 2011..gave iit in 2011

  47. anonymous
    • 5 years ago
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    lol you are brainy

  48. anonymous
    • 5 years ago
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    fine fine wrote AIEEE?

  49. anonymous
    • 5 years ago
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    thanx...aakash sahib kahan gaye...

  50. anonymous
    • 5 years ago
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    yeah..but marks nahi lagaye..wanted to be free

  51. anonymous
    • 5 years ago
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    Aakash went to temple .. will be right back soon he says.

  52. anonymous
    • 5 years ago
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    Are you on any IM ? What's your gtalk ?

  53. anonymous
    • 5 years ago
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    facebook...u in delhi?

  54. anonymous
    • 5 years ago
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    yes I am in Delhi.

  55. anonymous
    • 5 years ago
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    You ?

  56. anonymous
    • 5 years ago
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    wt school?

  57. anonymous
    • 5 years ago
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    Springdales

  58. anonymous
    • 5 years ago
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    you ?

  59. anonymous
    • 5 years ago
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    k.....add Himanish...studied at St. Columba's School

  60. anonymous
    • 5 years ago
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    http://www.facebook.com/profile.php?id=100002411313746

  61. anonymous
    • 5 years ago
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    ur pretty...g2g...ill add u

  62. anonymous
    • 5 years ago
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    thanks haha :) , sure.

  63. anonymous
    • 5 years ago
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    hey him... sorry .. now i realize my mistake .. u r rite ... we need to find the derivative of x^arcsin(x) and then multiply with diff of tan (x^arcsin(x))

  64. anonymous
    • 5 years ago
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    we find the first one using log .. as u said

  65. anonymous
    • 5 years ago
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    dont pste ur fb id on public pages....aakash....sk goyal ke phatte aise hi nhi maare..bye

  66. anonymous
    • 5 years ago
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    hun?

  67. anonymous
    • 5 years ago
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    Damn posted my fb profile here !

  68. anonymous
    • 5 years ago
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    toldya..b careful next tym

  69. anonymous
    • 5 years ago
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    r u a quizzer?

  70. anonymous
    • 5 years ago
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    quizzer ?

  71. anonymous
    • 5 years ago
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    what do you mean ?

  72. anonymous
    • 5 years ago
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    mean do u go fr quizzes and all?

  73. anonymous
    • 5 years ago
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    No , you ?

  74. anonymous
    • 5 years ago
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    yeah..i am..just inquiring whether uve heard of the columban open quiz...nvm...ive sent u d request

  75. anonymous
    • 5 years ago
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    what request ?

  76. anonymous
    • 5 years ago
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    btw what are you planning to study next after 12th ?

  77. anonymous
    • 5 years ago
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    engineering physics btech

  78. anonymous
    • 5 years ago
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    Oh , which university ?

  79. anonymous
    • 5 years ago
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    abhi result to aane do yaar..waise i think ill get into one of the IITs

  80. anonymous
    • 5 years ago
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    very nice.

  81. anonymous
    • 5 years ago
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    Was IIT easy this year ?

  82. anonymous
    • 5 years ago
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    How many hours do you study for IIT ? Went to any coaching ?

  83. anonymous
    • 5 years ago
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    yes..only i screwed up...

  84. anonymous
    • 5 years ago
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    narayana...no defined hours of study...

  85. anonymous
    • 5 years ago
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    went to any coaching classes at narayana or you stay at narayana ?

  86. anonymous
    • 5 years ago
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    assuming you mean "narayna" the area ..

  87. anonymous
    • 5 years ago
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    narayana iit academy

  88. anonymous
    • 5 years ago
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    Oh

  89. anonymous
    • 5 years ago
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    hav u added?

  90. anonymous
    • 5 years ago
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    Oh , wait i'll add now.

  91. anonymous
    • 5 years ago
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    hey

  92. anonymous
    • 5 years ago
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    how do you get an area under a function f(x) between spans x=a and x=b when you integrate it ?

  93. anonymous
    • 5 years ago
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    How come it fetches you the area ? intuition behind it ?

  94. anonymous
    • 5 years ago
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    no..

  95. anonymous
    • 5 years ago
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    No ?

  96. anonymous
    • 5 years ago
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    u divide the area under the graph into small strips along the x-axis, each having width dx

  97. anonymous
    • 5 years ago
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    Dude , gimme an IM. I cant login to facebook right now , my sis's logged in and if I log out , she'll scream , its her laptop. Give me your google talk or msn or yahoo or AIM or skype or whatever.

  98. anonymous
    • 5 years ago
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    these rectangular strips have height f(x) at point x, and width dx no IM now...my bits is on monday..sm1 sees m dead...

  99. anonymous
    • 5 years ago
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    lol

  100. anonymous
    • 5 years ago
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    so dA = f(x)dx

  101. anonymous
    • 5 years ago
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    now area is the summation of all these small areas

  102. anonymous
    • 5 years ago
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    \[A =\lim_{dx \rightarrow 0} \sum_{a}^{b}f(x)dx = \int\limits_{b}^{a}f(x)dx\]

  103. anonymous
    • 5 years ago
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    get it now?

  104. anonymous
    • 5 years ago
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    u cn call me if u want...m free after monday...only if ur comfortable with it

  105. anonymous
    • 5 years ago
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    samajh aaya?

  106. anonymous
    • 5 years ago
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    wait reading

  107. anonymous
    • 5 years ago
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    I will definitely call you on mind , if you dont mind getting disturbed.

  108. anonymous
    • 5 years ago
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    *monday not mind lol

  109. anonymous
    • 5 years ago
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    after monday..no disturbance frm gorgeous ppl...;)

  110. anonymous
    • 5 years ago
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    ill msg my no on fb kal dekhlena

  111. anonymous
    • 5 years ago
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    ;) sure. I understood the intuition somewhat now , cool. thanks

  112. anonymous
    • 5 years ago
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    no prob mis...ek din derivative bhi samjhaaoonga..bye g2g

  113. anonymous
    • 5 years ago
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    sure

  114. anonymous
    • 5 years ago
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    bye

  115. anonymous
    • 5 years ago
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    u preparing for iit?

  116. anonymous
    • 5 years ago
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    Not really , I think its too late now ? I never went to any coaching or prepared with IIT point of view.

  117. anonymous
    • 5 years ago
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    k..to yeh dabanng question kahaan se laye the?i think ur mind works in the right way..90 pc people don t even think abt d meaning f an integral

  118. anonymous
    • 5 years ago
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    lol really ? well I was just trying to understand how that works.

  119. anonymous
    • 5 years ago
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    Trust me yaar , am weak at maths. I dont do well at all.

  120. anonymous
    • 5 years ago
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    waise india ka education system is bakwas

  121. anonymous
    • 5 years ago
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    i msgd u my number

  122. anonymous
    • 5 years ago
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    Alright , surely will call you Mr. Brains.

  123. anonymous
    • 5 years ago
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    so wtr u doing now?

  124. anonymous
    • 5 years ago
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    just browsing. YouTube.

  125. anonymous
    • 5 years ago
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    You heard of Manipal ?

  126. anonymous
    • 5 years ago
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    university?my pals giving the exam tomorrow

  127. anonymous
    • 5 years ago
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    Yes. You dont have plans for that? I heard its good?

  128. anonymous
    • 5 years ago
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    Where is it actually?

  129. anonymous
    • 5 years ago
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    in the south .. good

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