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anonymous

  • 5 years ago

I have been trying to work this problem, it doesnt seem to have enough information. Chlorine is frequently used to disinfect swimming pools. The chlorine concentration should remain between 1.5 and 2.5 parts per million (ppm) for safe swimming. After a warm, sunny day only 80% of the chlorine may remain in the water, with the other 20% dissipating into the air or combining with chemicals in the water. Let model the concentration of chlorine in parts per million after t days. What is the initial concentration of chlorine in the pool?

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  1. amistre64
    • 5 years ago
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    your equation got lost in translation...

  2. anonymous
    • 5 years ago
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    I m just tryin to figure out how much initial concentration of chlorine in the pool

  3. amistre64
    • 5 years ago
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    "Let (......) model the concentration of chlorine in parts" the equation is missing. When you copy and pasted your question it ate the equation because it didnt recognize it

  4. amistre64
    • 5 years ago
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    if it aint an equation; then it ate whatever was witting there to begin with

  5. anonymous
    • 5 years ago
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    f(t)=3(0.8)^t

  6. amistre64
    • 5 years ago
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    well, it looks like we revert this to a table of times and try to make a recursion equation out of it

  7. amistre64
    • 5 years ago
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    A{n+1} = A{n} (.8) +C

  8. amistre64
    • 5 years ago
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    t=1; A = 2.4 t=2; A = 1.92 t=3; A = 1.536 1.92 = 2.4(.8) + C perhaps?

  9. amistre64
    • 5 years ago
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    C = 1.92 - (2.4*.8) C = 1.92 - 1.92 C = 0 maybe that works out lol

  10. amistre64
    • 5 years ago
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    C = 1.536 - (.8*1.92) C = 1.536 - 1.536 ... seems to be good

  11. amistre64
    • 5 years ago
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    2.4 = A{0}*.8 2.4\.8 = A{0} A{0} = 3 the inital amount was at 3 parts per mill if i read it right

  12. anonymous
    • 5 years ago
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    Ok so I have another quetions mathematically could the concentration ever be zero

  13. amistre64
    • 5 years ago
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    no; since the inital equation you gave can never have a zero component; the answer can never be 0; 3(0) = 0 but; .8^t never equals 0 0(.8^t) = 0 but; 3 never equals 0 so conclusion is: it can never reach zero

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