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anonymous
 5 years ago
cscθ+(cotθ/sinθ)=(sinθ+cosθ)/sin²θ.
Show as an identity.
Please help!
anonymous
 5 years ago
cscθ+(cotθ/sinθ)=(sinθ+cosθ)/sin²θ. Show as an identity. Please help!

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anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0cscθ+(cotθ/sinθ) =\[1/\sin \theta +\cos \theta/\sin^2\theta\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0\[\sin \theta +\cos \theta/\sin^2\theta\]
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