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anonymous
 5 years ago
2/3!+4/5!+6/7!+....to infinity is equal to?
anonymous
 5 years ago
2/3!+4/5!+6/7!+....to infinity is equal to?

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anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0What you've got there is a basic series...\[\sum_{n=0}^{\infty}\frac{n+2}{n!}\]Maybe you should try using the ratio test. That's what I'd first use to see if it converges.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0the series notation is wrong

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0i dont think so buddy

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Sorry, the sum's off. :P Don't have time to work it out right now, but I'm interested to see if anyone's got it to a concise form

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0which book r u using?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0"rudiments of mathematics" its a book for wbjee(west bengal joint entnc xm)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Wow, I wasn't even thinking. Try this\[\sum_{n=1}^{\infty}{\frac{2n}{(2n+1)!}}\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0(2n+2)/(2(n+3) *(2n+1)!/2n

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0(2n+2)/(2n+3)! *(2n+1)!/2n

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0wow so u got the expression right finally

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0\[2n+2 \over {(2n+2)(2n+3)(2n)}\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0\[\lim n \rightarrow \infty [1/2n(2n+3)\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0This just tell us that it converge but not to what

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.01/e= e^1[1+1/2! +1/3!...]^1 that can be expanded using binomial expension

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0\[[1+(1/2/!+1/3!...)]^{1}=1 (1/2!+1/3!...)+(1/2!+ 1/3!...)^2....\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0how come the sum is 2/3!+4/5!+6/7!+....?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0i dont kno. thats what the book says.. its wrong isn't it?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0seems to be, not sure

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0wow..great thinkin there buddy.. thanx!
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