A community for students.
Here's the question you clicked on:
 0 viewing
anonymous
 5 years ago
need some help with a difference equation
anonymous
 5 years ago
need some help with a difference equation

This Question is Closed

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0yn=8000(.80n)800o. Trying to solve for N. I know the answer I just need help with finding out how to get N alone and such. The answer should be like 13.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Im not sure if I need to divide by another number. I have another number and its 7560. Do I need to put the 7560 where the yn is

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0recurrence equation tends to get better results... 'difference' equation is the same thing, but a less used term

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0what was the original question? it seems like we are trying to jump into it halfway thru

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Ok, it says to use the solved difference equation to find in what calender year, the number of infected elm trees will be 7560. You must solve the solved difference equation: you may not guess and check. Get an equation for n and solve it.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Maybe my whole difference equation is wrong....

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0it might be; 'btm' asks alot of these questions and may have some insight

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0I might be able to help

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0imran is smart as well :)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0I can send you more information about the problem to maybe be able to help you more. There is like five questions to be answered.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0yn=8000(.80n)800y_o ?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0it should be 8000, no y_0

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0can you send me whole question

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0yes.Suppose a region has 8000 healthy elm trees. In 1950, bark beetles harboring the fungus arrive in the region. In each subsequent yera, the number of elm trees that contract the disease is 20% of the number of healthy trees at the end of the previous year. Once a tree is infected, it stays infected. Find the difference equation.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Also, to solve the difference equation, and use the solved difference equatoin to find in what calender year, the number of infected elm trees will be 7560. You must solve the solved difference equation.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0For my difference equation I have yn=〖.80〗_(yn1) y0=8000

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Okay, So I see you are solving for number of healthy trees. which is fine

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Infected trees y0=8000 y1=8000*(.8) y2= 8000*(.8)^2

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0*correction yn=8000*(.8)^n

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Total  Healthy trees= infected trees 80008000*(.8)^n=7560

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.08000*(.8)^n=75608000 8000*(.8)^n=440 (.8)^n=440/8000 .8^n=.055 log[.8,.555]=n n=12.99

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0ok. that does make much better sense. But how from 80008000(.80)^n, did u get 7560?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.07560 was given in your problem "the number of infected elm trees will be 7560"

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0In my book the normal difference equations are written as for example, yn=.8yn1 +9, yo=10. Do I need to put any of those into this new difference equation. The equation seems bare.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0your difference equation is \[y_n=y_{n1}*.8\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0alright that makes more sense now!!!

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0This is a difference equation for healthy trees

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0that should be it. Thank you so much for your help.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0hey imranmean, one more question. on the 8000(.80)n= 440, how did it come to Log[.8,.055]?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0\[8000*(.8)^n=75608000\] \[8000*(.8)^n=440\] \[(.8)^n={440\over8000}\] .8^n=.055 log[.8,.555]=n n=12.99
Ask your own question
Sign UpFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.