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he66666

  • 5 years ago

Grade 12 vectors: velocity? Mary leaves a dock, paddling her canoe at 3 m/s. She heads downstream at an angle of 30 degrees to the current, which is flowing at 4 m/s. How far downstream does Mary travel in 10s? Answer: about 66m How do you solve this? I don't know how to draw the diagram...

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  1. amistre64
    • 5 years ago
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    we know magnitude and direction of both vectors right?

  2. anonymous
    • 5 years ago
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    hey amistre got ya another one above this q when ur done mate

  3. amistre64
    • 5 years ago
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    we also have a scalar of 10

  4. amistre64
    • 5 years ago
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    scale the vectors then add them 30 degrees = has a unit vector of <sqrt(x),1> so at 3<sqrt(3),1> = <3sqrt(3),3> 10<3sqrt(3),3> + 10<0,4> = <30sqrt(3),30> < 0 ,40> --------------- <30sqrt(3), 70> right?

  5. amistre64
    • 5 years ago
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    the magnitude of this vector should be the distance traveled

  6. amistre64
    • 5 years ago
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    sqrt(70^2 + 30sqrt(3)^2) sqrt(4900 + 900(3)) sqrt(7600) right?

  7. amistre64
    • 5 years ago
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    87.1779... to find the distance travled downstream tho, we take this distance and multiply it by the cos(30) to get a vector projection

  8. amistre64
    • 5 years ago
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    what i come up with is: 75.49 but then I could be wrong

  9. amistre64
    • 5 years ago
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    did you typo the question?

  10. he66666
    • 5 years ago
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    No, there's no typo. But thanks amistre! :)

  11. anonymous
    • 5 years ago
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    ok i have a Q, how far did she paddle on the horizon before she went to the 30 degree angels downstream, some data is missing i believe

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