## anonymous 5 years ago √3x+6 (+6 is in radical)= x-4

1. anonymous

square both sides to get rid of square root

2. anonymous

square (x-4)---FOIL

3. anonymous

$3x + 6 = x^{2} -8x + 16$

4. anonymous

subtract 3x and 6 to move to right side leaving 0 on the left

5. anonymous

$x^{2} -11x - 10 =0$

6. anonymous

you can factor using chart or my grouping

7. anonymous

sorry that should be +10

8. anonymous

$x^{2} - 11x + 10 =0$

9. anonymous

what factors of 10 as a product gives you -11 as a sum? -1 * -10=10 and -1 + (-10)=-11

10. anonymous

so the factors are -1 and -10 (x-1)(x-10)=0 x-1 = 0 and x-10=0 x=1 x=10 {1, 10}

11. anonymous

or factoring by grouping-break down middle term using know factors of -1 and-10

12. anonymous

$x^{2}-x-10x+10$

13. anonymous

factor out GCF x(x-1)-10(x-1)=0 (x-10)(x-1)=0 x=10 and x=1

14. anonymous

thx

15. anonymous

16. anonymous

im in 8th doing algebra, so what ur final answer?

17. anonymous

and what are you talking about with a medal?

18. anonymous

love 8th grade Algebra! Solutions are 10 and 1 {1, 10}

19. anonymous

click on good answer by my name on the right

20. anonymous

yeah i got that, but when you plug it back in, it doesnt work. does it have to work?

21. anonymous

22. anonymous

it does work

23. anonymous

$x=1 \sqrt{9}=1-4$

24. anonymous

okay good, thanks for your help

25. anonymous

square root of 9 is 3 or -3

26. anonymous

wait could u also help me with another question instead of me reposting one??

27. anonymous

sure

28. anonymous

x=10 so square root of 36 equals -6 or 6

29. anonymous

a right triangle has one leg that is 4 inches shorter than the other leg. the hypotenuse is √106 inches. find the lengths of the legs.

30. anonymous

ok i'm writing it out to solve...hold on

31. anonymous

k

32. anonymous

ill be right back

33. anonymous

do you want to factor my grouping

34. anonymous

$2x^{2}-8x-90=0$

35. anonymous

let a = x, b=(x-4) and c=square root of 106(hypotenuse)

36. anonymous

$x^{2} + x^{2} -8x +16 = 106$

37. anonymous

after plugging into Pythagorean Theorem (right triangle)

38. anonymous

subtract 106 from both sides to get the first equation I posted above

39. anonymous

back

40. anonymous

working backwards so hope you can follow

41. anonymous

kind of

42. anonymous

where did you get lost?

43. anonymous

http://www.twiddla.com/536745 go there for explanation

44. anonymous

thx