anonymous
  • anonymous
if k belongs to real no. and middle term of (k/2+2)^8 is 1120 . find alue of k.
Mathematics
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SOLVED
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chestercat
  • chestercat
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amistre64
  • amistre64
(k/2)+2 ??
amistre64
  • amistre64
1+8+28+56+70+56+28+8+1 then for a start right?
amistre64
  • amistre64
(k/2)^8 +8(2) (k/2)^7 +28(2)^2 (k/2)^6 +56(2)^3 (k/2)^5 +70(2)^4 (k/2)^4 +56(2)^5 (k/2)^3 +28(2)^6 (k/2)^2 +8(2)^7 (k/2) +(2)^8

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anonymous
  • anonymous
(k/2+2)=1120
amistre64
  • amistre64
the middle terms is: 70*2^4*(k/2)^4 = 1120
anonymous
  • anonymous
want to find value of k
amistre64
  • amistre64
70.16.k^4/16 = 1120 70.k^4 = 1120 k^4 = 1120/70
amistre64
  • amistre64
k = 4root(112/7) then
anonymous
  • anonymous
oo sorry (k/2+2)^8=1120
amistre64
  • amistre64
it said 'middle term' = 1120 ; you still want that?
anonymous
  • anonymous
ya
amistre64
  • amistre64
k = 4rt(16) = 2 k = +- 2; but id go with 2
anonymous
  • anonymous
ok. thanks
amistre64
  • amistre64
70.16.(2^4/16) = 1120 70.16 = 1120 1120 = 1120 :)

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