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anonymous
 5 years ago
Find a unit vector parallel to and normal to the graph of f(x) at the indicated point. f(x) = sqrt(25x^2) point (3,4)
anonymous
 5 years ago
Find a unit vector parallel to and normal to the graph of f(x) at the indicated point. f(x) = sqrt(25x^2) point (3,4)

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amistre64
 5 years ago
Best ResponseYou've already chosen the best response.1y = sqrt(25x^2) at point (3,4) the derivative gives us the slope at 3 to be: 2x  at x=3: 3/4 2sqrt(25x^2)

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.1so we have a vector that is parallel to the slope of the tangent line is: <4,3> right?

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.1the mag = 5 so; unit tangent = <4/5 , 3/5>

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.1since perp lines have a 1 product between slopes we get the normal to be... <3/5,4/5>

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Correct! It is <4,3> because it is rise over run. Rise is y component of vector and run is x component of vector. Thank you.
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