Android
  • Android
What is standard form of this hyperbola? 9y^2 - 16x^2 - 144 = 0 Then I can graph it.
Mathematics
  • Stacey Warren - Expert brainly.com
Hey! We 've verified this expert answer for you, click below to unlock the details :)
SOLVED
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
katieb
  • katieb
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
anonymous
  • anonymous
Hyperbolas are of the form\[(x-h)^{2}/a +(y-k)^{2}/b=1\]
Android
  • Android
How do I convert it to that?
anonymous
  • anonymous
Use intuition, from your equation how can you get a one on the right and at the same time some number under x and y?

Looking for something else?

Not the answer you are looking for? Search for more explanations.

More answers

Android
  • Android
Add 144 to the 0?
anonymous
  • anonymous
Great, you're on the right track, continue.
Android
  • Android
Would I now divide the 9 and 16 by 144?
anonymous
  • anonymous
Yes
Android
  • Android
Is that the final answer? 9y^2/144 - 16x^2/144 = 1
anonymous
  • anonymous
9 can divide 144, and 16 into 144
Android
  • Android
Divide 9 by 44?
anonymous
  • anonymous
You want a^2 and b^2 at the bottom, so divide 144 by 9 and so on
Android
  • Android
9y^2/16 - 16x^2/12 = 1
anonymous
  • anonymous
You're on the right track, you should cancel the 9 and 16 and calculations off a little on b\[(y-0)^{2}/4^{2} -(x-0)^{2}/3^{2}=1\]Good job
Android
  • Android
Thanks

Looking for something else?

Not the answer you are looking for? Search for more explanations.