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anonymous
 5 years ago
Evaluate the integral with the aid of an appropriate usub:
Integral sign { cos^19 (x)}^1/2 sinx dx
anonymous
 5 years ago
Evaluate the integral with the aid of an appropriate usub: Integral sign { cos^19 (x)}^1/2 sinx dx

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anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0tailor made for usub. put \[u=cos(x)\] \[du=sin(x)dx\] \[\int u^{\frac{19}{2}}du\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0I see what I did wrong, I messed up the power. The whole cos^19 (x) messed me up. Thanks for your help, I appreciate it. : )

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0You should get \[\int\limits_{}^{}\sin ^{1/2}{(u ^{19})} du\] From here you may have to jump into some trig identity im not sure

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0actually there is no \[sin^{\frac{1}{2}}\] in it. just take the anti derivative of \[u^{\frac{9}{2}}\] which is \[\frac{2}{11} u^{\frac{11}{9}}\] and then replace u by cos(x) don't forget the "" sign in front like i did.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0oops i meant the antiderivative is \[\frac{2}{11}u^{\frac{11}{2}}\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0the problem they wrote there is \[\int\limits_{}^{}\sin ^{1/2}[\cos ^{19}(x)]*\sin(x)*dx\]
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