anonymous
  • anonymous
Compute the distance Mark will run if he continues using the formula, y = 10(1.1)x, for 52 weeks (one year). Does this distance seem reasonable? A. yes B. no
Mathematics
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anonymous
  • anonymous
Compute the distance Mark will run if he continues using the formula, y = 10(1.1)x, for 52 weeks (one year). Does this distance seem reasonable? A. yes B. no
Mathematics
katieb
  • katieb
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anonymous
  • anonymous
x exponent
anonymous
  • anonymous
does it represent weeks or years
anonymous
  • anonymous
the x exponent represents both i think bc 52 weeks is one year isnt it?

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anonymous
  • anonymous
yes but if you use years then you would use 1 versus 52(weeks)
anonymous
  • anonymous
usually years unless otherwise stated in problem
anonymous
  • anonymous
So then lets use 52 weeks (: for the answer i got 1291.3miles in 52 weeks
anonymous
  • anonymous
if you use 52 then you should get 1420.42932
anonymous
  • anonymous
Hmmmm so what do you think the answer would be? (:
anonymous
  • anonymous
what are the units
anonymous
  • anonymous
seems reasonable from what info you gave and if we use 52
anonymous
  • anonymous
alright so the answer would be true? >.< kinda confused lol
anonymous
  • anonymous
If y is the distance traveled in x weeks, then, as btm said, the distance traveled is: \[y=10(1.1)^{52}\approx1,420\] So, Mark would run 1420 length unit in 52 weeks.

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