Prove that the area of an isosceles right triangle is one-fourth the square of the length of the hypotenuse.
Stacey Warren - Expert brainly.com
Hey! We 've verified this expert answer for you, click below to unlock the details :)
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga.
Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus.
Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
Two sides equal in length
If I make a straight line dividing the isosceles triangle it makes two right triangles inside it
In order to prove this you need to set up an isosceles right triangle, find the area, find the length hypotenuse.
Not the answer you are looking for? Search for more explanations.
how when there are no numbers provided?
You put in your own numbers, dummy numbers, or you can use letters to represent all numbers.
ok... thank you.
IF I plug in 5 for my base and 3 for my height I get an area of 7.5 I can calculate the hypotenuse 3^2 + 5^2 = c^2
9 + 25 = c^2
34 = c^2
5.83 as my third side...
what is my next step of how to prove the area of an isosceles triangle is one-fourth the square of the length of the hypotenuse?
is this it?
yes thank you
An isosceles right triangle is a 45-45-90 triangle with sides of x and hypotenuse of sqrt(2)x
x^2 +x^2 = (sqrt(2)x)^2
2x^2 = 2x^2
We know the area of triangle is 1/2 base*height, where base and height are both x
A = 1/2*x^2
Hypotenuse is sqrt(2)x -> Hypotenuse^2 = (sqrt(2)x)^2 = 2x^2
1/4*2x^2 = 1/2*x^2
Therefore Area is 1/4 of Hypotenuse^2
oh my goodness... you did good... I just have to understand it in english now lol thank you!!
sorry i only speak english so cant help you there :)