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anonymous

  • 5 years ago

Use summation given below to find a function that it represents

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  1. anonymous
    • 5 years ago
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    \[\sum _{n=1}^{\infty } \text{nx}^n\]

  2. anonymous
    • 5 years ago
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    \[x/(x-1)^2\]

  3. anonymous
    • 5 years ago
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    how did you get it?

  4. anonymous
    • 5 years ago
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    give me a second

  5. anonymous
    • 5 years ago
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    I will post this question again

  6. anonymous
    • 5 years ago
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    anything?

  7. anonymous
    • 5 years ago
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    yeah, sorry, busy busy, here it goes

  8. anonymous
    • 5 years ago
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    \[\sum_{1}^{∞}n x ^{n} = x * \sum_{1}^{∞}n x ^{n-1} = x * d/dx[\sum_{1}^{∞} x ^{n}] = x * d/dx[1/(1-x)] = x/[(1-x)^{2}]\] Excuse me for the poor formating but the website doesn't offer much of choice. The star (*) stands for multiplication. Thanks.

  9. anonymous
    • 5 years ago
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    Hey there's one catch: correct this: \[x * d/dx[\sum_{0}^{n} x ^{n}]\] Because when we differentiate, n->0 not n->1 Thanks

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