Let the function f be defined by y = f(x), where x and f(x) are real numbers. f(x)=8 over x-4 f(2) f(-3) f(k) f(k^2-1)=

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Let the function f be defined by y = f(x), where x and f(x) are real numbers. f(x)=8 over x-4 f(2) f(-3) f(k) f(k^2-1)=

Mathematics
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its really just a matter of plugging in those f numbers in place of the x
\[f(2)=\frac{8}{2-4}\] \[f(-3)=\frac{8}{-3-4}\] \[f(k)=\frac{8}{k-4}\] \[f(k^2 -1)=\frac{8}{k^2 -1-4}\]
sweet.. that is what i came up with on this one.. and i beleive if i simplify the f(2)= 8 over2-4 it comes out to -4... is that correct?

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yes, thats right

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