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anonymous
 5 years ago
If we have a graph of data which has:
Time (t) (hours) verses Ln(Population) and the data goes as follows:
Time (hours)  1 2.5 5 7 12 15 18
Ln(Pop)  (2.89)(3)(3.13)(3.3)(3.61)(3.83)(4.03)
Dont mind the brackets^ (just to separate the numbers)
The question asks to investigate whether this is an exponential growth pattern =/.. In words how would i explain it is an exponential pattern?
anonymous
 5 years ago
If we have a graph of data which has: Time (t) (hours) verses Ln(Population) and the data goes as follows: Time (hours)  1 2.5 5 7 12 15 18 Ln(Pop)  (2.89)(3)(3.13)(3.3)(3.61)(3.83)(4.03) Dont mind the brackets^ (just to separate the numbers) The question asks to investigate whether this is an exponential growth pattern =/.. In words how would i explain it is an exponential pattern?

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anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Try graphing the points and seeing of the resulting curve is in the form of an exponential.

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0plot the points and see what they look like on a graph is my solution

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0you can see if its linear by taking the slope between a few points and see if they match

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0you could also assume it exponential and try to determine a formula for it

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0use discrete recursion equations maybe?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Lagrange polynomials?

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0y = b*a^x and solve for the solutions?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0I've already graphed it and it looks linear, however,the assignment is based on exponentials =/

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0yes, it does match linearly quite well; but perhaps we are just to close to it so that it looks linear?

myininaya
 5 years ago
Best ResponseYou've already chosen the best response.1m1=(3.833.61)/(1512)=11/150 m2=(3.613.3)/(127)=.062 not linear

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Jhonte was able to find a linear formula though?

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0jhon found a best fit match; not quite the same as 'its linear'

myininaya
 5 years ago
Best ResponseYou've already chosen the best response.1are we doing linear regression?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Yeah thats the best fit.

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0the trouble with best fit; is that we learn in calculus that if we look close enough at a curve it becomes straight

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0the earthis flat after all :)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0So what myininaya post earlier: m1=(3.833.61)/(1512)=11/150 m2=(3.613.3)/(127)=.062 How does this show it is not linear?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0linear functions have one slope

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0linear has the same slopes; those are 2 different slopes

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0its derivative is a constant, whereas this function's derivate changes signs more than once is not

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0it looks like a polynomial to me

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0So, if i were to explain this was an exponential growth pattern. I could include why it is not linear and what else could i perhaps add to support this argument?

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0donuts; they work good for proving your point :)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Thanks to everyone that helped :D <3. Ill just mention why it isn't linear :P!

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Oh damn it! is was meant to ask, could you explain to me what Fruitless said earlier: "its derivative is a constant, whereas this function's derivate changes signs more than once is no"

myininaya
 5 years ago
Best ResponseYou've already chosen the best response.1do you know anything about calculus?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Yeah, but does he mean to derivative of Ln(population)?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0I meant the slopes increase/decrease variably between points, so I am assuming it is a polynomial.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Not negatively decrease, I mean decrease relative to the previous slope.

myininaya
 5 years ago
Best ResponseYou've already chosen the best response.1hey so jhonte, you are going to argue that it is an exponential function right? You could say it is possible since it the function keeps increasing.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Alright thanks alot :D!

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0So, all in all.. An exponential growth pattern increases faster as x increases?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Not exactly... It is exponential growth as long as the function increases; the slope cannot be less than 0.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0In this case the function increases each time doesn't it?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Yes. That could be one of your arguments to support that it is an exponential.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0THANKS SO MUCH OMG YOU GUYS ROCK!

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0One second, sorry for bringing the topic back up, but does the ln of data have to show a linear graph?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0If you are assuming it is exponential, then make a curve "approximation" between each two points.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0I think I've missed an import piece of data in being the Population (millions) 18 20 23 27 37 46 56

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0I found the ln(pop) from those

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0I'm being told the ln(population) verse time graph must be linear....

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0My current argument is: The Ln(Population) verse Time graph at first glance looks linear, however, we are able to prove it is infact not linear by finding the gradient at different points and seeing if the gradient is constant. So, to find the gradient we use m= (y2y1)/(x2x1) Therefore, we know y = Ln(Population) and x = Time. Now we find the gradient at any random points. m1=((3.833.61))/((1512))=0.73 m2= ((3.613.3))/(127)=0.62 It becomes evident to as why this is not a linear growth pattern. Inorder to be linear the gradient has to be constant throughout. Another key in stating whether a graph is an exponential growth pattern is by indentifying whether the function increases and it’s slope doesn’t equal less than 0. In this case we are able to conclude this is in fact an exponential growth pattern as it’s function does increase throughout.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0I agree with your argument.
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