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Try graphing the points and seeing of the resulting curve is in the form of an exponential.

plot the points and see what they look like on a graph is my solution

you can see if its linear by taking the slope between a few points and see if they match

you could also assume it exponential and try to determine a formula for it

use discrete recursion equations maybe?

Lagrange polynomials?

just shoot me now :P

y = b*a^x and solve for the solutions?

m1=(3.83-3.61)/(15-12)=11/150
m2=(3.61-3.3)/(12-7)=.062
not linear

Jhonte was able to find a linear formula though?

jhon found a best fit match; not quite the same as 'its linear'

are we doing linear regression?

Yeah thats the best fit.

the earthis flat after all :)

hahah true :P

linear functions have one slope

linear has the same slopes; those are 2 different slopes

Oh, okay

its derivative is a constant, whereas this function's derivate changes signs more than once is not

it looks like a polynomial to me

donuts; they work good for proving your point :)

lol

ahaha

Thanks to everyone that helped :D <3. Ill just mention why it isn't linear :P!

ok good luck

thank you :)

do you know anything about calculus?

Yeah, but does he mean to derivative of Ln(population)?

I meant the slopes increase/decrease variably between points, so I am assuming it is a polynomial.

Not negatively decrease, I mean decrease relative to the previous slope.

Yeah

Alright thanks alot :D!

So, all in all.. An exponential growth pattern increases faster as x increases?

In this case the function increases each time doesn't it?

Yes. That could be one of your arguments to support that it is an exponential.

THANKS SO MUCH OMG YOU GUYS ROCK!

Thanks :)

If you are assuming it is exponential, then make a curve "approximation" between each two points.

I think I've missed an import piece of data in being the
Population (millions) 18 20 23 27 37 46 56

I found the ln(pop) from those

I'm being told the ln(population) verse time graph must be linear....

I agree with your argument.