anonymous
  • anonymous
the lenght of a rectangle is fixed at 16cm. What widths will make the perimeter greater than 92cm?
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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schrodinger
  • schrodinger
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anonymous
  • anonymous
Length has to be greater fixed at 16 and it has to be a rectangle. Thus, 2(16) + 2(x) > 92. Equate X from this formula. Hope that helps.
anonymous
  • anonymous
not really, I am still confused? what is the answer?
anonymous
  • anonymous
2x > 92 -32 2x > 60 x > 30cm A rectangle has two lengths and 2 widths. Thus, if the length has to be 16 cm, the other side of it has to be 16 cm for it to still be a rectangle. This leaves with the two identical widths. So since it must be more than 92cm, the widths total should be more than 60 cm. Therefore, each width has to be more than 30 cm. I know it's kinda weird the widths are longer than the length. :/

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