anonymous
  • anonymous
the lenght of a rectangle is fixed at 16cm. What widths will make the perimeter greater than 92cm?
Mathematics
katieb
  • katieb
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Get this expert

answer on brainly

SEE EXPERT ANSWER

Get your free account and access expert answers to this
and thousands of other questions

anonymous
  • anonymous
Length has to be greater fixed at 16 and it has to be a rectangle. Thus, 2(16) + 2(x) > 92. Equate X from this formula. Hope that helps.
anonymous
  • anonymous
not really, I am still confused? what is the answer?
anonymous
  • anonymous
2x > 92 -32 2x > 60 x > 30cm A rectangle has two lengths and 2 widths. Thus, if the length has to be 16 cm, the other side of it has to be 16 cm for it to still be a rectangle. This leaves with the two identical widths. So since it must be more than 92cm, the widths total should be more than 60 cm. Therefore, each width has to be more than 30 cm. I know it's kinda weird the widths are longer than the length. :/

Looking for something else?

Not the answer you are looking for? Search for more explanations.