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anonymous

  • 5 years ago

how would you solve sin2x=0.5?

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  1. anonymous
    • 5 years ago
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    sin(2x)=.5 2x=arcsin(.5) x = arcsin(.5)/2

  2. anonymous
    • 5 years ago
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    No but without a calculator?

  3. anonymous
    • 5 years ago
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    That is without a calculator.

  4. anonymous
    • 5 years ago
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    but how would you find the arcsin of .5/2?

  5. anonymous
    • 5 years ago
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    the actual number... i would use newton approximation

  6. anonymous
    • 5 years ago
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    lol. im only in precal -_- sorry i dont know about that

  7. amistre64
    • 5 years ago
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    sin(30) = 1/2 30 = 2x x = 60

  8. amistre64
    • 5 years ago
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    x also = 120

  9. amistre64
    • 5 years ago
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    ....make that 15 lol

  10. amistre64
    • 5 years ago
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    and 180-15

  11. anonymous
    • 5 years ago
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    sin(x)=1/2 x = pi/6 sin(2x)=.5 x = pi/3

  12. anonymous
    • 5 years ago
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    pi/12, sorry

  13. anonymous
    • 5 years ago
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    wait wait wait hold on. Wouldnt x=15. Since sin of 30=.5? And sin of 2(15)=.5?

  14. anonymous
    • 5 years ago
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    In degrees it would be 15, in radians, pi/12

  15. anonymous
    • 5 years ago
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    ahhhhhh. oh ok. See now i know what im doing. bcuz at first i didnt even understand what the problem was asking me to find out.

  16. anonymous
    • 5 years ago
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    Thank you thank you. :)

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