anonymous
  • anonymous
show me how to work 4y=12y^2
Mathematics
jamiebookeater
  • jamiebookeater
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anonymous
  • anonymous
what have you done so far?
amistre64
  • amistre64
-4y from each side; then factor out a y and see which y values make it equal zero
anonymous
  • anonymous
did you just say subtract 4y from both sides?

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anonymous
  • anonymous
nothing i dont understand how to work it
amistre64
  • amistre64
yes
anonymous
  • anonymous
umm thats wrong.... more like divide.
anonymous
  • anonymous
thats what i thought it would be division
amistre64
  • amistre64
4y = 12y^2 ; -4y 0 = 12y^2 -4y ; factor out 4y 0 = 4y(3y - 1) ; y = 0 or 1/3
anonymous
  • anonymous
^2 means squared right that's why i typed it like that because 12y squared
anonymous
  • anonymous
so 4y=12y squared
amistre64
  • amistre64
am i still 'wrong' ? lol
anonymous
  • anonymous
oh sorry yeah do it like he said and check using quadratic.
anonymous
  • anonymous
ok i'm a 9th grader so i'm a bit confused lol
amistre64
  • amistre64
you can also /4y if you want 1 = 3y ; y=1/3 but your missing something because... 4y CAN be a zero, which this way does not allow for
amistre64
  • amistre64
if it can be zero; stay away from division
anonymous
  • anonymous
\[4y=12y^2\]\[4y-4y=4y^2-4y\]\[0=4y^2-4y\]\[4(y^2-y)=0\]\[4(y(y+1))=0\]
anonymous
  • anonymous
yes good thinking ^-^
anonymous
  • anonymous
*12y^2
amistre64
  • amistre64
when you know it can never be zero; then division is fine ;)
anonymous
  • anonymous
ok ty

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