anonymous
  • anonymous
question in the reply :)
Mathematics
  • Stacey Warren - Expert brainly.com
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schrodinger
  • schrodinger
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
anonymous
  • anonymous
Continuous uniform distribution? Many students find that sitting through an entire lecture is difficult to do without falling asleep. Suppose the number of minutes a single, randomly selected student is asleep during a lecture is uniformly distributed between 7 and 14 minutes. B) Over the course of the semester (say, 50 lectures), what is the probability that a randomly selected student will sleep a total of between 130 and 140 minutes? Assume that the minutes slept in any lecture is independent of the number of minutes slept in any other lectures. (C) How many lectures must a student attend to be 95% sure that they will have slept at least 28 minutes in total? Use the quadratic equation to solve for the quadratic in this question. Hint: replace x with sqrt(n) to solve for n.
M
  • M
need more information. need equation to work with.
anonymous
  • anonymous
im not sure what the equation is, thats the problem

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M
  • M
then you can't solve those questions unfortunately
M
  • M
maybe you can lol
anonymous
  • anonymous
ye i tried. not sure how tho.
M
  • M
formula is \[1/(\beta - \alpha)\]
M
  • M
1/(14-7)
anonymous
  • anonymous
r u sure? thats what i used for the first part of this question. this part seems more complicated?
M
  • M
1/7 for 7 < x < 14
M
  • M
1/7x from 7 to 14
M
  • M
if you integrate that formula i gave you then it becomes 1/7 (x) you follow up to that?
M
  • M
i mean 1/7(x) from 130 to 140 mins
anonymous
  • anonymous
ohkay
anonymous
  • anonymous
so the sample size 50 goes where?
M
  • M
you have the final answer by any chance
anonymous
  • anonymous
lol no i dont
M
  • M
the number of lecture should matter because it's uniform random variable
M
  • M
so answer should be approx. 1.4286
anonymous
  • anonymous
how do u get that?
M
  • M
you integrate 1/7 you get (1/7)x then you take the limit from 140 to 130
M
  • M
are you sure it's 140 and 130 mins?
anonymous
  • anonymous
yeah it is
M
  • M
hmm maybe you're supposed to divide the minutes by 50 lectures
anonymous
  • anonymous
maybe haha.
M
  • M
i think you're supposed to do that then you get .02857 = 2.857%
anonymous
  • anonymous
ok. wud u be able to tell me how u got the limit form 130 to 140?
M
  • M
you first divide 140/50 and 130/50 to get 2.8 and 2.6
M
  • M
then you (1/7)(2.8) - (1/7)(2/6) = .0287
M
  • M
(1/7)(2.8) - (1/7)(2.6) = .0287
anonymous
  • anonymous
ohh okay.thanks :) do u kno how to do parrt C?
M
  • M
not sure since i didn't learn this using quadratic only hypergeometric :( sorry
M
  • M
and binomial
M
  • M
look at your notes and set it equal to .95
M
  • M
good luck
anonymous
  • anonymous
kays np. thanks for ur help :)
anonymous
  • anonymous
lol theres a medal for u :)

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