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anonymous

  • 5 years ago

question in the reply :)

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  1. anonymous
    • 5 years ago
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    Continuous uniform distribution? Many students find that sitting through an entire lecture is difficult to do without falling asleep. Suppose the number of minutes a single, randomly selected student is asleep during a lecture is uniformly distributed between 7 and 14 minutes. B) Over the course of the semester (say, 50 lectures), what is the probability that a randomly selected student will sleep a total of between 130 and 140 minutes? Assume that the minutes slept in any lecture is independent of the number of minutes slept in any other lectures. (C) How many lectures must a student attend to be 95% sure that they will have slept at least 28 minutes in total? Use the quadratic equation to solve for the quadratic in this question. Hint: replace x with sqrt(n) to solve for n.

  2. M
    • 5 years ago
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    need more information. need equation to work with.

  3. anonymous
    • 5 years ago
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    im not sure what the equation is, thats the problem

  4. M
    • 5 years ago
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    then you can't solve those questions unfortunately

  5. M
    • 5 years ago
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    maybe you can lol

  6. anonymous
    • 5 years ago
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    ye i tried. not sure how tho.

  7. M
    • 5 years ago
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    formula is \[1/(\beta - \alpha)\]

  8. M
    • 5 years ago
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    1/(14-7)

  9. anonymous
    • 5 years ago
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    r u sure? thats what i used for the first part of this question. this part seems more complicated?

  10. M
    • 5 years ago
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    1/7 for 7 < x < 14

  11. M
    • 5 years ago
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    1/7x from 7 to 14

  12. M
    • 5 years ago
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    if you integrate that formula i gave you then it becomes 1/7 (x) you follow up to that?

  13. M
    • 5 years ago
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    i mean 1/7(x) from 130 to 140 mins

  14. anonymous
    • 5 years ago
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    ohkay

  15. anonymous
    • 5 years ago
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    so the sample size 50 goes where?

  16. M
    • 5 years ago
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    you have the final answer by any chance

  17. anonymous
    • 5 years ago
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    lol no i dont

  18. M
    • 5 years ago
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    the number of lecture should matter because it's uniform random variable

  19. M
    • 5 years ago
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    so answer should be approx. 1.4286

  20. anonymous
    • 5 years ago
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    how do u get that?

  21. M
    • 5 years ago
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    you integrate 1/7 you get (1/7)x then you take the limit from 140 to 130

  22. M
    • 5 years ago
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    are you sure it's 140 and 130 mins?

  23. anonymous
    • 5 years ago
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    yeah it is

  24. M
    • 5 years ago
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    hmm maybe you're supposed to divide the minutes by 50 lectures

  25. anonymous
    • 5 years ago
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    maybe haha.

  26. M
    • 5 years ago
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    i think you're supposed to do that then you get .02857 = 2.857%

  27. anonymous
    • 5 years ago
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    ok. wud u be able to tell me how u got the limit form 130 to 140?

  28. M
    • 5 years ago
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    you first divide 140/50 and 130/50 to get 2.8 and 2.6

  29. M
    • 5 years ago
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    then you (1/7)(2.8) - (1/7)(2/6) = .0287

  30. M
    • 5 years ago
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    (1/7)(2.8) - (1/7)(2.6) = .0287

  31. anonymous
    • 5 years ago
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    ohh okay.thanks :) do u kno how to do parrt C?

  32. M
    • 5 years ago
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    not sure since i didn't learn this using quadratic only hypergeometric :( sorry

  33. M
    • 5 years ago
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    and binomial

  34. M
    • 5 years ago
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    look at your notes and set it equal to .95

  35. M
    • 5 years ago
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    good luck

  36. anonymous
    • 5 years ago
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    kays np. thanks for ur help :)

  37. anonymous
    • 5 years ago
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    lol theres a medal for u :)

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