anonymous
  • anonymous
Solve this differential equation by eliminating the arbitrary constants. y=Acos(log x) + Bsin(log x)
Mathematics
schrodinger
  • schrodinger
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anonymous
  • anonymous
the equation or differential equation?
anonymous
  • anonymous
diffrential eqn
anonymous
  • anonymous
but where are the differentials?

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anonymous
  • anonymous
you have to eliminate A & B
anonymous
  • anonymous
i guess this is the prob to form a DE
anonymous
  • anonymous
Yea DE.
anonymous
  • anonymous
question makes no sense
anonymous
  • anonymous
eq contains 2 constants, differentiate twice n solve
anonymous
  • anonymous
how this makes no sense? this is que from book. @ elecengineer
anonymous
  • anonymous
Yea But M unable to solve.can u help me in differentiating?
anonymous
  • anonymous
y'=-Asin(logx)(1/x)+Bcos(logx)(1/x) y''=-Acos(logx)(-1/x^2)-Bsin(logx)(-1/x^2) =(1/x^2)[Acos(logx)+Bsin(logx)] y''=(1/x^2)y
anonymous
  • anonymous
okay thank u so much uzma let me check
anonymous
  • anonymous
what :|

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