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anonymous
 5 years ago
Solve this differential equation by eliminating the arbitrary constants.
y=Acos(log x) + Bsin(log x)
anonymous
 5 years ago
Solve this differential equation by eliminating the arbitrary constants. y=Acos(log x) + Bsin(log x)

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anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0the equation or differential equation?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0but where are the differentials?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0you have to eliminate A & B

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0i guess this is the prob to form a DE

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0question makes no sense

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0eq contains 2 constants, differentiate twice n solve

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0how this makes no sense? this is que from book. @ elecengineer

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Yea But M unable to solve.can u help me in differentiating?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0y'=Asin(logx)(1/x)+Bcos(logx)(1/x) y''=Acos(logx)(1/x^2)Bsin(logx)(1/x^2) =(1/x^2)[Acos(logx)+Bsin(logx)] y''=(1/x^2)y

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0okay thank u so much uzma let me check
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