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anonymous

  • 5 years ago

what would your bounds be if you were looking for the area of the polar function r=2+4cosx but not including the small loop. the picture is in this link: http://tutorial.math.lamar.edu/Classes/CalcII/PolarArea.aspx Example 1

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  1. anonymous
    • 5 years ago
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    The bigger one is a specific shape, I forgot the name, it is given as a question or problem all the time. I don't know if the cos thing is different from that one given, but it has its own name and cosine thingy.

  2. anonymous
    • 5 years ago
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    right, but if you were looking for the total area of that, what would be the bounds of the integral?

  3. anonymous
    • 5 years ago
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    It would have something that looks just like the other one. Let me find. One guy was here the other day asking tons of questions about it.

  4. anonymous
    • 5 years ago
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    i think it could be from 0 to 2pi/3

  5. anonymous
    • 5 years ago
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    It's called a cardioid r=a(1-costheta)

  6. anonymous
    • 5 years ago
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    yes, thank you. Do you agree with my proposed bounds?

  7. anonymous
    • 5 years ago
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    In double integrals, I think it goes 0 to 2 pi. But it is such a familiar shape (I think its in medical, it looks like an eyeball) it is easily done in single integral. The integral of (1/2) r^2 dtheta

  8. anonymous
    • 5 years ago
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    Now the info I gave you was for the cardioid without the inner loop. With it, a different approach.

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