anonymous
  • anonymous
what would your bounds be if you were looking for the area of the polar function r=2+4cosx but not including the small loop. the picture is in this link: http://tutorial.math.lamar.edu/Classes/CalcII/PolarArea.aspx Example 1
Mathematics
  • Stacey Warren - Expert brainly.com
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jamiebookeater
  • jamiebookeater
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anonymous
  • anonymous
The bigger one is a specific shape, I forgot the name, it is given as a question or problem all the time. I don't know if the cos thing is different from that one given, but it has its own name and cosine thingy.
anonymous
  • anonymous
right, but if you were looking for the total area of that, what would be the bounds of the integral?
anonymous
  • anonymous
It would have something that looks just like the other one. Let me find. One guy was here the other day asking tons of questions about it.

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anonymous
  • anonymous
i think it could be from 0 to 2pi/3
anonymous
  • anonymous
It's called a cardioid r=a(1-costheta)
anonymous
  • anonymous
yes, thank you. Do you agree with my proposed bounds?
anonymous
  • anonymous
In double integrals, I think it goes 0 to 2 pi. But it is such a familiar shape (I think its in medical, it looks like an eyeball) it is easily done in single integral. The integral of (1/2) r^2 dtheta
anonymous
  • anonymous
Now the info I gave you was for the cardioid without the inner loop. With it, a different approach.

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