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anonymous

  • 5 years ago

if \[\log_{\sin x}\cos x-1+\log_{\sin x}\sin 2x \] then the values of x are

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  1. anonymous
    • 5 years ago
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    i assume that + means = then cot x = sin2x sinx = +1/root2 , -1/root2

  2. anonymous
    • 5 years ago
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    oh crap! \[\log_{\sin x}\cos x=1+\log_{\sin x}\sin 2x\] this is the Q

  3. anonymous
    • 5 years ago
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    although it doesnt differ much from what you assumed=)

  4. anonymous
    • 5 years ago
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    did u get it now??

  5. anonymous
    • 5 years ago
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    how did you simplify the log terms bro??

  6. anonymous
    • 5 years ago
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    write 1 as log(sinx) to base sinx

  7. anonymous
    • 5 years ago
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    then bring it to the other side..it becomes log(cotx) to base sinx

  8. anonymous
    • 5 years ago
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    ok got it..no need to xplain nemore buddy=)

  9. anonymous
    • 5 years ago
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    thnx

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spraguer (Moderator)
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