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anonymous
 5 years ago
How do i turn a growth function with respect to height with respect to time into acceleration with respect to time?
anonymous
 5 years ago
How do i turn a growth function with respect to height with respect to time into acceleration with respect to time?

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anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Differentiate it twice.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0wait distance / time :P

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Yeah differentiate the function with respect to time.

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.1height is a position derive it once to find the change in height with respect to time; which is speed, also known as velocity, or how fast the growth is. derive again to find the change in velocity, which is acceleration.

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.1derivatives are 'how something changes compared to something else'. Graphically, that represents slope right? how much does the y value change when you move the x?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Well, I Have a huge problem regarding loggerpro...

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0We did an experiment where we used mentos & coke inorder to investigate exponential growth patterns ect.. Now I'm struggling to realise why my raw data is linear and Ln data is exponential...

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Now this is my raw data. (I've tired to make it exponential :P

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.1that looks like a bounded exponential

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.1in other words, the data starts out looking linear, but there is a limit that it approaches

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Another picture, this is of my (initial) raw data and the Ln of height

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0red = raw and blue = Ln(height)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0ignore the first graph.

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.1how did you obtain the data? what were the ...... ignore function activated :)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0But still... do understand what I mean?

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.1almost; can you show me the table that the data comes from? your experiment?

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.1so did you come up with a good: y(s) = s function ?

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.1the time taken to reach the meters? what does position have to do with time?

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.1and of course the higher it gets the slower it goes :)

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.1i wrote a program that can fit this to a quadratic :)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0i got y=0.5604x0.8171

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Do you know how to expain it being a quadratic?

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.1it would be a best fit line as well

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.1the most basic option would be to take the slope from one point to the next; table that up; and see what it looks like

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0yeah, but the next question asks: How well do these functions fit your graphs? Are they a perfect fit? Explain your answer

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0What we are meant to do is determine the function for the graphs

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.1perfect fit? any real life experiments are never gonna perfectly fit a model

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0There is one argument :)

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.1models are ideals; real life experiments contain to many variables to account for

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0so how do i use this quadratic program?

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.1you plug in three data points and it takes them to figure out the quadratic that bends to those points; then to test for accuracy, I used a feature to put in a random 'x' point to see if the quadratic is good enough

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.1another option is to do a method of 'least squares' which i forget the steps to :)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Alrighty, so ive got the quadratic: 0.807801462732185x^2 + 11.760157128268668x + 40.60929764207282

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0cause what I have to do is work out the equations for each graph, preferable manually.. then predict the spray for 5 mentos.. Justify your response in mathematical reasoning..

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.1i didnt see a table option for 'number of mentos'

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.1and remember to use diet coke and the minty mentos....

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0We have already conducted the experiment its just if i were able to work out 1 i'd be able to do the others :) However, for number of mentos there is one for 4/7/9

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Heheh you're my last hope now :P

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.1mythbusters did an episode on this menthos thing; try to check out their work :) get some ideas if you havent already

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.1that cut it short lol just google mythbusters mentos

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0No idea if this is allowed, but do you use skype?

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.1aint got the periphials for it.....

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0I just want to screen share or something :L

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.1do you know how to draw a vector field?

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.1you strat out with something like this; and for each point you find the slope (y/x) and plug a vector representation of it at the point to see where the data is moving

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.1they prolly have online stuff to do it quicker and easier tho

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.1in fact, they proly have online best fit calculators too :)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0O i can best bit in autograph, its just.. I need to beable to work it out manually. :C

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.1manually can be a pain; especially with alot of data points and decimals involved; that reason we have computers is to use as a tool to help us; it aint a cheat ya know :)

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.1they teach you the manually so that you have the concept of why it works and how to get to an answer when you aint got the tools avaiable; but before computers it took alot of good mena dnwomen and a few good trout many years to do a single math problem
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