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anonymous
 5 years ago
f(x) = x5
g(x)= x^3
h(x)= √x^2+1
Write this expession as a composition, using only the functions f,g and h.
√ (x^3  5)^2 + 1
Does anyone know how to do this please? I have an exam coming up and I would appreciate it.
anonymous
 5 years ago
f(x) = x5 g(x)= x^3 h(x)= √x^2+1 Write this expession as a composition, using only the functions f,g and h. √ (x^3  5)^2 + 1 Does anyone know how to do this please? I have an exam coming up and I would appreciate it.

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amistre64
 5 years ago
Best ResponseYou've already chosen the best response.1the copy and paste technique tends to cut off the top of the radical. Can you tell us what is spossed to be 'under' the radical?

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.1(h o f o g)(x) is one way to write this thing

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.1h(f(x)) = sqrt. f(x)^2 + 1 f(g(x)) = g(x)  5 g(x) = x^3 its like nesting functions; you fit them into each other like a set of russian dolls

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0It is all meant to be under it. I was thinking that was the answer but I don't know how to work it out. Could you please tell me how you got the answer?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Thank you so much for your help. I understand it a lot better now.

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.1i simply used the facts they gave and tore the new equation apart to investigate its inner workings

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.1we had to rip out the 'x' part and re constuct it with the missing pieces

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.1sqrt. ______ ^2 +1 ; h(x) matches the profile , h(f(g(x))) /\ _______  5 ; f(x) matches the profile, f(g(x)) /\  ; g(x) matches the profile

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Yeah that makes sense thanks.
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