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anonymous
 5 years ago
A particles position as a function of time is given by u = cos 2t i+sin 2t j ( The u, i and j should have tilde's underneath as they are vectors)
(a) find the equation of the path
anonymous
 5 years ago
A particles position as a function of time is given by u = cos 2t i+sin 2t j ( The u, i and j should have tilde's underneath as they are vectors) (a) find the equation of the path

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amistre64
 5 years ago
Best ResponseYou've already chosen the best response.1x = cos(2t) y = sin(2t) z = 0

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0thats not the answer i sorta know how to do it but the 2t throws me off abit

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.1thats the equation of a line in R^3 :) well, except for an initial point

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.1the position path just produces a unit circle

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0yes i understand that but normally you would eliminiate the sin and cos by squaring x and y then adding them

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0im not sure what happens to the 2t

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.12t just modifies the speed of rotation; nothing more

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.1its going twice as fast around the unit circle

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0i see so the working is like this; x = cos 2t y=sin2t x^2=cos^2t y^2=sin^2t x^2+y^2=1 i ignore the 2t correct

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.1or simply redefine it; 2t = u

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.1it has no importance on position; other than it a given t it is at this location; but the path remains unchaged by it

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.1tell me; does a person walking along the sidewalk get to the same place as the person jogging on the sidewalk?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0yes thats correct. thanks so much you actually made me understand the question.
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