anonymous
  • anonymous
find the equation of the path described by the following vector. u=t^2+4/(t+2)^2 + 4t/(t+2)^2
Mathematics
chestercat
  • chestercat
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amistre64
  • amistre64
thats a mean looking vector
anonymous
  • anonymous
lol yeah
amistre64
  • amistre64
the left side is usually the 'x' component; which leaves the other to be the 'y' component

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amistre64
  • amistre64
they have the same bottoms on i see that
anonymous
  • anonymous
it gives a hint to factorise but im not sure how to use it
amistre64
  • amistre64
t^2 +4 + 4t (t+2)(t+2) ------------ = --------- = 1 (t+2) (t+2) (t+2)(t+2)
amistre64
  • amistre64
y = 1 with a hole at -2 i think
amistre64
  • amistre64
x+y = 1 y = -x then
anonymous
  • anonymous
lol the answers is y=1-x
amistre64
  • amistre64
...... or that lol
anonymous
  • anonymous
wait yeah thats right
anonymous
  • anonymous
didnt see the second answer lol
amistre64
  • amistre64
it is? como es posible?
anonymous
  • anonymous
lol thanks heaps ur a genius

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