write the equation of the parabola with focus (1, -3) and vertex (5, -3)??

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write the equation of the parabola with focus (1, -3) and vertex (5, -3)??

Mathematics
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it opens to the left
the a value = 4 y^2 =16x modify for off centered
alright thanks, but how did you know that

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Other answers:

opps; opens left
the line between the vertex and foci is straight along the y = -3 axis
the vertex is the bend and the focus is inside the curve
the distance from the vertex to the focus is the "a" value in the parabola formula from geometery
y^2 = -4ax
is that the directrix?
the directix is on the other side of the vertex; the distance 'a'
the directix would be at x=9
ok
thank you
youre welcome :) the complete answer is: (y+3)^2 = -16(x-5)
lol thanks again :)
do you know what the latus rectum of a ellipse is?
sounds painful; .... i prolly do, but just dont know the proper term for it :)
haha i was out of school and i come back i was like wtf???
it is defined as the chord running thru the focus
mhmm
amistre64 come back to mine please
(y+3)^2 = -16(x-5) plug in x = 1 -16(-4) = y^2 + 9 + 6y = -64 y^2 +6x +73 = 0
6x shoulda been 6y
the latus rectum is the line thru the foci and those y values
but thats a parabola right? the ellipse's equation is (x-3)^2/16 + (y+6)^2/4 = 1
i forgot how to multiply lol
http://www.google.com/search?q=latus+rectum+ellipse&oe=utf-8&rls=org.mozilla:en-US:official&client=firefox-a&um=1&ie=UTF-8&tbm=isch&source=og&sa=N&hl=en&tab=wi&biw=1024&bih=622
same concept; its the line thru the focus that runs perp to the center line
oh ok well, thank you
we got about a min b4 they shut the site down for maintainence
dang

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