The width of a retangle is fixed at 21cm. What length will make the perimeter greater then 76cm?

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The width of a retangle is fixed at 21cm. What length will make the perimeter greater then 76cm?

Mathematics
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ok well I have go this far I think. a retangle has four sides. two sides are fixed at 21cm so that would be 42cm. they want it to be greater then 76.
if you substract 76-42=34 divide by 2 =17 so can 17 be the answer to the question?
or it could be 18 cause that is larger also. so it would be 42+36= 78

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Go slow. the width is 21, therefore 2(21)
Call the length x, therefore 2x
2*21=441
2w + 2l > 76 This is the general equation, use your numbers from what I posted above to put in this equation.
441>76
the width is 21*2=441
so would that be 441+?=
You are locked in on something, and apparently ignored everything I have written.
well you have said 2w which is = width correct
The width is 2(21) that is given but that is not equal to 441?! That is mathematical nonsense.
I am trying to understand. Ok well I took it as 2*21 sry!!!!!
The perimeter is twice width and twice length. So the equation is 2(21)+2x>76
that is 42 sry I wrote it wrong.
That is the equation, in the equation x represents the length. Depending on what answer your teacher wants you present the equation or you solve for x if you specifically want the length.
it just say the lenght must be greater then ? cm.
that is why I am came up with the answer that I have had.
I gotten 2x+42 so far
Solve the equation and the answer x>17. You got this same answer earlier so you are apparently doing the right thing. I have just put in a neat equation so that if you have to explain it to your little brother he would understand it.
so the answer is 17 for the lenght correct
You don't have to ask me, just solve the equation for x; and remove all doubt. But your language and phraseology is wrong: the length must be GREATER THAN 17.
I know sorry I am not good at this but I got the correct answer.
Good job

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