anonymous
  • anonymous
How do I graph the solution of the following system 2x+y≤4, y-1≤0 x≥0, y≥0 I am not sure what the equations should be
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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katieb
  • katieb
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anonymous
  • anonymous
do u need answer the one factor by group?
anonymous
  • anonymous
y-1≤0 -------> y ≤ 1 and y≥0 ------> 0 ≤ y ≤ 1 2x+y≤4 y ≤ 4 - 2x can u graph this?
anonymous
  • anonymous
I need to graph the solution on a graph and show the equations

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anonymous
  • anonymous
i guess I needto find the slope intercept form?
anonymous
  • anonymous
u can graph this ? y = x y = -x y = -2x y = 4 - 2x
amistre64
  • amistre64
you also need to know if there are any 'and' , 'or's involved
anonymous
  • anonymous
no ands or ors
anonymous
  • anonymous
just the equation and a blank graph
amistre64
  • amistre64
1 Attachment
amistre64
  • amistre64
the solution is the shaded area; those points are common to all the graphs
amistre64
  • amistre64
the how is like this: we have a boundary curve that breaks the graph into 2 areas; one above a curve and the one below it; right?
anonymous
  • anonymous
yes
amistre64
  • amistre64
that boundary curve will either be a part of the solution or not; but since your inequalities say 'equal to' than we can include the curves, still with me?
amistre64
  • amistre64
to determine which side of the curve is a solution; we pick a point that is not on the curve; becasue we want to determine an area that is not the curve right? that point can easily be 0,0 or if that ones taken; pick (0,1) or (1,0) or something easy to compute
amistre64
  • amistre64
if the point on the side you choose makes the inequaility true? then that side is a solution; and if false, then you need to choose the other side to shade right?
amistre64
  • amistre64
if we have multiple equations, then we either want to know what area will make any of them true; or all of them true; this problem seems to be asking for the area of the graph that makes all of the inequalities true...
amistre64
  • amistre64
so we need to find the areas that overlap .... make sense?
amistre64
  • amistre64
if i ask you to pick everybody that is on your left; where do you look for solutions to the task?
anonymous
  • anonymous
amistre how to make a graph like that in pc?
amistre64
  • amistre64
alot of detailing in 'paint' program lol
amistre64
  • amistre64
i made a blank like this; and then i detail it when i need to
1 Attachment
anonymous
  • anonymous
wow
anonymous
  • anonymous
thank you

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