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do u need answer the one factor by group?
y-1≤0 -------> y ≤ 1 and y≥0 ------> 0 ≤ y ≤ 1 2x+y≤4 y ≤ 4 - 2x can u graph this?
I need to graph the solution on a graph and show the equations
i guess I needto find the slope intercept form?
u can graph this ? y = x y = -x y = -2x y = 4 - 2x
you also need to know if there are any 'and' , 'or's involved
no ands or ors
just the equation and a blank graph
the solution is the shaded area; those points are common to all the graphs
the how is like this: we have a boundary curve that breaks the graph into 2 areas; one above a curve and the one below it; right?
that boundary curve will either be a part of the solution or not; but since your inequalities say 'equal to' than we can include the curves, still with me?
to determine which side of the curve is a solution; we pick a point that is not on the curve; becasue we want to determine an area that is not the curve right? that point can easily be 0,0 or if that ones taken; pick (0,1) or (1,0) or something easy to compute
if the point on the side you choose makes the inequaility true? then that side is a solution; and if false, then you need to choose the other side to shade right?
if we have multiple equations, then we either want to know what area will make any of them true; or all of them true; this problem seems to be asking for the area of the graph that makes all of the inequalities true...
so we need to find the areas that overlap .... make sense?
if i ask you to pick everybody that is on your left; where do you look for solutions to the task?
amistre how to make a graph like that in pc?
alot of detailing in 'paint' program lol