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anonymous
 5 years ago
Use the RAtional Root Theorem to list the possible rational roots for the followin equation.
f(x)=x^2+2x+1
anonymous
 5 years ago
Use the RAtional Root Theorem to list the possible rational roots for the followin equation. f(x)=x^2+2x+1

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amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0factors last#  factors first#

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0since allthe signs are + there are no + roots

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0I dont know this Rational root theorm, but what I see from the constant term is......possible roots are the factors of the constant term. factors of 1 are, 1 and 1 so possible roots are + 1

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0rational means fraction and the therum says we cannarrow our trial and error down to a pool of options that have a chance of working

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0if it aint inthe list; ther eis no way it could work :)

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0or at least no easy way to get it; maybe have to involve square roots then

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.05x^2 +6x +9 we can generate a pool of options buy factoring last over top 1,3,9  1,5

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0but here, though +1, 1 are possible roots, we can trail and error with these, and what works best.

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0so our roots can be: 1,3,9,1/5, 3/5, 9/5 +

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0It requires me to show the work does this look right? (x+1)^2 x+1=0 x=0 x+1=0 x=1 answer 1

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0that doesnt look lke it applies to your question

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0your problem says to generate the pool options: 1 (+)  ; generates 2 option for us, 1 and 1 1

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0a friend was trying to help me and I wasn't sure

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0then you try and error your way thru it: when x = 1; we try to use (x1) as a factor; divide it thru to see

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0or synthetic divide it for a quicker result

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0my other problems require testing synthetically possibilities

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0so the way you show it is how I should write it?

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0synthetic is the same concept as long division; but neater

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0yes; find the rational root options by: last# factors (+)  first# factors

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0then you pull out all the numbers that these make....

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0this is a course that I probable should have taken in a classroom setting I had to take it through an independent program for high school in order to graduate next month
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