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factors last# ---------- factors first#
+- 1 --- 1
since allthe signs are + there are no + roots
I dont know this Rational root theorm, but what I see from the constant term is......possible roots are the factors of the constant term. factors of 1 are, 1 and -1 so possible roots are +- 1
rational means fraction and the therum says we cannarrow our trial and error down to a pool of options that have a chance of working
if it aint inthe list; ther eis no way it could work :)
or at least no easy way to get it; maybe have to involve square roots then
5x^2 +6x +9 we can generate a pool of options buy factoring last over top 1,3,9 ----- 1,5
but here, though +1, -1 are possible roots, we can trail and error with these, and what works best.
so our roots can be: 1,3,9,1/5, 3/5, 9/5 +-
It requires me to show the work does this look right? (x+1)^2 x+1=0 x=0 x+1=0 x=-1 answer -1
that doesnt look lke it applies to your question
your problem says to generate the pool options: 1 (+-) -- ; generates 2 option for us, 1 and -1 1
a friend was trying to help me and I wasn't sure
then you try and error your way thru it: when x = 1; we try to use (x-1) as a factor; divide it thru to see
or synthetic divide it for a quicker result
my other problems require testing synthetically possibilities
so the way you show it is how I should write it?
synthetic is the same concept as long division; but neater
yes; find the rational root options by: last# factors (+-) ----------- first# factors
then you pull out all the numbers that these make....
this is a course that I probable should have taken in a classroom setting I had to take it through an independent program for high school in order to graduate next month