## anonymous 5 years ago solve. 2log4-log3+2logx-4=0

2log4-log3+2logx-4=0 Equivalent to $\log(16/3)+\log(x ^{2})=4$ then $\log(16x ^{2}/3)=4$ you will get $x^{2}=10^{4}\times3\div16$ solve using calculator you will get 43.3 (1 decimal)