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anonymous
 5 years ago
the region enclosed by the graphs of y=e^(x/2), y=1, and x=ln3 is revolved about the xaxis. Find the volume of the solid generated??????? I NEED CALCULUS HELP PLEASE
anonymous
 5 years ago
the region enclosed by the graphs of y=e^(x/2), y=1, and x=ln3 is revolved about the xaxis. Find the volume of the solid generated??????? I NEED CALCULUS HELP PLEASE

This Question is Closed

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0easy? lol i would love your help then :)

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0lets see where these curves meet; and what our boundaries are

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0e^(x/2) = 1 when x=0 right?

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0x = ln(3) is just a constant; we can find it on a calculator

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0let me draw a pic of my interpretation of the bonds then

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0i think they intersect at 0 and ln3 but i dont know how to integrate it

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0theres only two things to integrate here; from 0 to ln(3) right?

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0lets find the volume of the top curve; then we will cut out the section below y=1ok

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0yes that would work but im suppose to do something with (pie)

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0pi {S} [e^(1/2(x))]^2 dx ; [0,ln(3)]

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0what is e^(x/2)^2 =? e^x right?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0yes because they would cancel

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0the key here is to realize that we are adding up all the areas of circles that have been sliced; the area of a circle = pi r^r it just so happens the r = f(x)

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0so; [f(x)]^2 = e^(x/2)^2 = e^x pi {S} e^x dx ; [0,ln(3)] whats the integral of e^x?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0the antiderivetive? its justs e^x

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0e^x is its own derivative; so its its own integral :) yes

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0pi [ e^(ln(3)) e^(0) ] = ?

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0pi [ e^(ln(3))  e^(0) ] = ?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0an example my teacher did shows it being {S} (pi (e^x)1) and then taking the antiderivetive of that

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0lets stay on one track here; well jump the track when we get to the end

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0ok i understand that i just dont understand where the minus 1 came from?

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0right now we are making a solid piece; we will then cut out the senter

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0pi [e^(ln3)  e^0] = ??

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0o so we r taking the whole volume minus the part we dont need which is the y=1

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0exaclty :) we can do it in parts or all togther; makes no difference

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0gotcha and i got 2 for that answer

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0good :) now let integrate y = 1 from 0 to ln(3); or do you know a shortcut for this one?

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0pi {S} 1 dx ; [0,ln3] becomes?

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0good :) 2pi  ln(3) pi is your answer then

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0pi [ 2  ln(3)] even lol

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0and that is what the back of the book says...you are good lol

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0toldja it was easy lol

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0adding up areas of circles; thats all

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0yea i just suck at it when my teacher tries to explain it..i may need more help in a few

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0im sure well be around

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0u still there? i have a quick question?
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