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anonymous
 5 years ago
anyone a pro with differential equations? It has been too long and I need some help
anonymous
 5 years ago
anyone a pro with differential equations? It has been too long and I need some help

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anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0I feel ok with them, not pro but hopefully I can help

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0\[y'''+y=0 \] where y(o)=0 , y'(0) =1, y''(0)= 0 thank you please help

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0sorry I cannot help, havent done 3rd order ones.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Ok how about find all solutions to y'2y=1 thank you for trying

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0you can multiply with an integrating factor, do you remember that?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0I will get a pen and paper

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0thank you I know its alot of work

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0so do you know the technique of integrating factor?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0you r the best lets see if I get it :)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0you want to make a full derivative out of the left hand side

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0for this you need to have something like dy/dx+ some y=whatever

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0my computer is slowing down sorry ...yes I remeber that

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0no problem, what is the integrating factor here?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0after we integrate x dx on the other side

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0it is \[e ^{\int\limits_{}^{} the multiplier of y}dx\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0the integral of 2 is 2x (you dont need the constant here) so multiply through by \[e ^{2}\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Im sorry the computer wont let me type

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0It keeps stopping but I am here reading...Yes I remeber now the 2x

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0the result is \[e ^{2x}\] dy/dx 2 e^{2x} y=e ^{2x}

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0do you recognise the full derivative now?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0yes it is coming back to me

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0what about when we have a trig function like y''+4y=cos x

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0this is harder but my favourite :)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0better your fav than mine :) :) i have not done these in 17 years it is so hard to remember you r a big help

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0first you have to think of the homogeneous equation (meaning y''+4y=0) you have to find the general solution for that, for this we use the auxiliary equation. that just says that ay''+by'+cy=0 and write a quadratic equation for it,\[a \lambda ^{2}+b \lambda +c=0\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0or in the form of e^x

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0here you will have to solve y^2+4=0

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0I will be back in 5 min

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0i have no idea Im trying to follow along with you and my book but so confused I need to watch a tutorial i think and i will be bac

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0you can only solve this with complex numbers

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0you had enough? How is it that after 17 years you are doing this again?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0http://www.analyzemath.com/calculus/Differential_Equations/second_order.html This page explains it quite well

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0i am a teacher but needed 2 credits of advanced math i truly didnt want to take up your time

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0I will have an exam about this in 2weeks so it is not a waste of time for me

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0I need alot of explanation and my computer is not cooperating ...to be honest this work is due tomorrow and my brain is blank we can continue if u want to help me..

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0well it is up to you, I am free now for an hour

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Consider the equation y' + (cos x) y= e^sinx find the solution that satisfies \[\phi\](\[\pi\] ) = pi

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0what is the end bit? that isnt clear

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0I guess you have to use the integrating factor here as well. it will be e^integral(cosx) so e^sinx.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0that way you get \[(e ^{sinx}y)'=1\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0so the LHS= x+C y=(x+C)/e^sinx
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