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anonymous

  • 5 years ago

I'm stuck on this problem can someone tell me if this is right so far? (a)find the discriminant: (b)classify the root(s) as 2real (uneaqual) roots, 1 (double) root, or 2 imaginary conjungate roots: (c)find the roots x^2-2x=-5 my answer x=1+2i,1-2i

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  1. anonymous
    • 5 years ago
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    discriminant is \[b^2-4ac\] in your case a = 1, b = -2 and c = 5 because first you have to write \[x^2-2x+5=0\] to identify a, b and c. so you get \[(-2)^2-4\times 5=4-20=-16\] since this is negative it means you have two imaginary roots. \[x^2-2x=-5\] \[(x-1)^2=-5+1=-4\] \[x-1=\pm \sqrt{-1}=\pm 2i\] \[x=1\pm 2i\] you got it.

  2. anonymous
    • 5 years ago
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    typo above. i meant \[x-1=\pm \sqrt{-4}=\pm 2i\]

  3. anonymous
    • 5 years ago
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    yes thank you

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