## anonymous 5 years ago I'm stuck on this problem can someone tell me if this is right so far? (a)find the discriminant: (b)classify the root(s) as 2real (uneaqual) roots, 1 (double) root, or 2 imaginary conjungate roots: (c)find the roots x^2-2x=-5 my answer x=1+2i,1-2i

1. anonymous

discriminant is $b^2-4ac$ in your case a = 1, b = -2 and c = 5 because first you have to write $x^2-2x+5=0$ to identify a, b and c. so you get $(-2)^2-4\times 5=4-20=-16$ since this is negative it means you have two imaginary roots. $x^2-2x=-5$ $(x-1)^2=-5+1=-4$ $x-1=\pm \sqrt{-1}=\pm 2i$ $x=1\pm 2i$ you got it.

2. anonymous

typo above. i meant $x-1=\pm \sqrt{-4}=\pm 2i$

3. anonymous

yes thank you