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m of arc XY = 100 degrees m of arc YZ = 120 degrees and m of arc ZX = 140 degrees
m arc 1 is angle XQZ M angle 2 is angle YQZ m of angle 3 is angle WQZ ??? how do I answer this
I also know the m of angle 4 is 30 degrees I need to find the measure of angle 5 which is angle XZQ
Can someone draw this circle and help me? Please
itll have to wait; might not be back on. the library is closing up and i have to find another wifi spot...
ok boo thank you... I'll be here
how do we modify this?
thats good... now... ummm let me see
you have it labeled correctly
now, draw an internal line in the circle from Y to Z
an internal line from Z to X. Q is the center point
A line from Q to Z as well
A line from Y to Q and a line from X to Q... kind forms a wierd triangle with a radius QZ
between XY with Q as the center Angle XQY is angle 1, Angle YQZ is angle 2 and Angle ZQX is angle 3
Angle 4 is the angle Y makes umm... Angle QYZ and angle 5 is XZQ same triangle as Angle 3
you have a prnt scrn button :)
Q is the center of the circle...
that allows you to take a screen shot of whateves on the monitor; open up a pint program; and paste it in there and modify it :)
ok let me try this.. never did it before
where is the paint program? I copied and pasted it into word. ??
start; accessories; paint is usually the path to take
start; programs; accessories; paint...
found it one moment
it is aint it lol
ok how to I copy and paste it? It looks a little junky but ha first time user... Just as long as you get the point....
save it to your desktop; then 'attach file' it to the post
ha mybe I sould have made it bigger
its good :)
so whats the question tat goes with this :)
This is inscribed angles and arcs, I have to find angle 1, 2 , and 3 and 5
Ha thanks LOL
Find the measures of those angles
ang1 = arc.yx
ang2 = arc.yz
in the beginning of my problem Arc XY:arc YZ:Arc ZX = 5:6:7
not sure why proportions are in this
5 6 7 probably give you a unit measure but yeah, its added detail i think
ang3 = arc.xz
yes to angle 1 yes to angle 2
yep to angle 3
ang5 = (180-arc.xz)/2
I know from the back of the book angle 4 is 30 degrees
it was an odd number :(
ang4 = (180 - arc.yz)/2 if you wanna check mymethod here
ang5 = 20?
180 - 140 = 40/2 = 20 right?
ummm yes it looks like a smaller angle... I'm trying to see if angle 4 is working out... sorry ... slow motion over here... :)
180-120 = 60/2 = 30
where did 140 come from? and how did you know that?
xy = 100; yz = 120; zx = 140 interior angles at center; 1 = 100; 2 = 120; 3 = 140
yeah where did those come from... I know 360 is a circle but how did you know to divide those accordingly?
all triangles from the center are isosoles; if youknow the inside angle the other two are (180-inside)/2 since they are equal angles
the measure of the arc isnt a length, its a distance rotated; shich is why its in degrees
an arc length of 90 degrees mens they turned it 90 degrees lol
once you know the interior central angles; the other angles are equal in size; and all triangles add up to 180 degrees inside them
180-central angle = whats left over whats left over/2 is the only thing they an be lol
hey angle 4 comes out right!!!! Oh wow this is complicated stuff!!!
what about angle 1, 2 and 3?? is that all in here? LOL
angle 1 would be 180 - xy/2?
You are very smart!!!! and thank you for all you have taught me!!!!
ha the paint too!!!
ang1 = its arc length that it is in front of:) and youre welcome
there are no lines to determine angles associated with ang1
angle 1 comes out 40
but if you did put a line ther; then yes, that would be how you find them
yes; the complement angles to 1 would have been 40 :)
ha oh boy.... its 100
yes; ang1 is 100 :)
Ok I should be good I understand, I think thats cause the angle is on the center... not in one of them triangles... right?
Angle 1I'm talking about...
Okay... I'll zip the lip!!! LOL thanks!
right; center angle sweeps out an arc length of # degrees that arc length is
if arc length = 120 degrees, then angle has to be 120 degrees
completely makes sense!
you are a rock star!!!