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safia21
 5 years ago
Ryan drives 10mi/h slower than Maya, And it takes ryan 1 hour longer to travel 300 miles. How long does it take Maya to make a trip
safia21
 5 years ago
Ryan drives 10mi/h slower than Maya, And it takes ryan 1 hour longer to travel 300 miles. How long does it take Maya to make a trip

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sandra
 5 years ago
Best ResponseYou've already chosen the best response.0I'll let amistre get this :p

sandra
 5 years ago
Best ResponseYou've already chosen the best response.0well, you need two equations and two variables to be able to solve this

sandra
 5 years ago
Best ResponseYou've already chosen the best response.0one variable is the time it takes Maya to take the trip, and one variable is the time it takes ryan to take the trip

safia21
 5 years ago
Best ResponseYou've already chosen the best response.0I got 300(x)= 300(x1) + 10x(x1)

sandra
 5 years ago
Best ResponseYou've already chosen the best response.0well, actually, let's make the two variables the speed of each person  then we can easily solve for how long it takes maya to drive 300 miles. So: 1. R = M  10 2. 300/R  300/M = 1

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0i think i have an answer.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0i got 60 but it was kind of a pain the way i did it. maybe an easier way.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0i used maya's rate as r, ryan's as r  10 and then \[\frac{300}{r}=\frac{300}{r10}+1\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0that is ryan's time is one hour more than maya's.

sandra
 5 years ago
Best ResponseYou've already chosen the best response.0right. yeah that makes sense

safia21
 5 years ago
Best ResponseYou've already chosen the best response.0sorry but i do not understand

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0i made a mistake somewhere i am trying again.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0first of all the answer: ryan travels at 50 mpr and maya at 60. it is easy to check: \[d=rt\] \[t=\frac{d}{r}\] if maya travels 300 miles at 60 miles an hour she makes the trip in \[\frac{300}{60}=5\] hours while ryan takes \[\frac{300}{50}=6\] hours or one hour longer. so this is the correct answer.

safia21
 5 years ago
Best ResponseYou've already chosen the best response.0O i understand thank you!

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0well i got the correct answer, but i am trying to find the right algebra to solve it for you.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0whew finally. ok here goes. ready?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0ok we use \[t=\frac{d}{r}\] and we know that ryans rate is r10 and his maya's time is one less than ryan's. Maya's time is \[\frac{300}{r}\] and ryan's is \[\frac{300}{r10}\] and \[\frac{300}{r}1=\frac{300}{r10}\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0that says maya's time is one less than ryans. to solve for r, easiest to subtract first on the left hand side: \[\frac{300r}{r}=\frac{300}{r10}\] now cross multiply: \[(r10)(300r)=300r\] mutiply out \[300r3000r^2+10r=300r\] subtract 300r \[3000 r^2+10r=0\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0thought i had \[(r60)(r+50)=0\] so r = 60 but i seem to have made another mistake somewhere. i will try to find it.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0oh lord. i put the one on the wrong side! should have been \[\frac{300}{r}+1=\frac{300}{r10}\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0maya's time plus one gives ryans time. ok now. \[\frac{300+r}{r}=\frac{300}{r10}\] \[(300+r)(r10)=300r\] \[300r 3000+r^210r=300r\] \[r^210r300=0\] \[(r60)(r+50)=0\] \[r=60\] or \[r=50\] which makes no sense in this problem so \[r=60\] sorry it took a while.

safia21
 5 years ago
Best ResponseYou've already chosen the best response.0its okay and thanks again

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0sorry i made a mistake originally. hope it was not too confusing.
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