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anonymous

  • 5 years ago

1/3logx + 4log(x+5) Please show work!

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  1. anonymous
    • 5 years ago
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    what are you supposed to do?

  2. anonymous
    • 5 years ago
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    Write each as a single logarithm, sorry.

  3. anonymous
    • 5 years ago
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    oh that is easy, just remember the basic logarithm rules

  4. anonymous
    • 5 years ago
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    http://www.purplemath.com/modules/logrules.htm

  5. anonymous
    • 5 years ago
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    first change 1/3logx into log ((x^1/3)) and 4log (x+5) into log (x+5)^4 and not log a + logb= log ab So log(x+5)^4)*x^1/3) is the result

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